The value of p+q = 403,For the given complex number a+bi and
where p and q are co-primes
F(z)= (a+ib)z⇒this is equidistant from "0" and "z"
Given modulus of complex number (a+ib) = 10 ; p and q ∈Z
G.C.D of ( p and q)=1
(a+ib)z equidistant from "0" and "z"
p = 399 and q= 4
p+q= 399+4
p+q=403
Hence the value of p+q = 403
Complete question:A function f is defined on the complex number by f (z) = (a + bi)z, where 'a' and 'b' are positive numbers. This function has the property that the image of each point in the complex plane is equidistant from that point and the origin. Given that |a+bi|=8 and that where p and q are coprime. Find the value of (p+q)
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Answer:
[1] x - 4y = 22
[2] 2x + 5y = -21
Step-by-step explanation:
Solve equation [1] for the variable x
[1] x = 4y + 22
// Plug this in for variable x in equation [2]
[2] 2•(4y+22) + 5y = -21
[2] 13y = -65
// Solve equation [2] for the variable y
[2] 13y = - 65
[2] y = - 5
// By now we know this much :
x = 4y+22
y = -5
// Use the y value to solve for x
x = 4(-5)+22 = 2
I am sorry if I get it wrong.
In a trapezoid the angles add up to 360 so 360-(90+90+65)=115
So, 30 is the perimeter. We are told the table is twice as long as it is wide.
So, we have think of 2 numbers, one being twice as big than the other. So, it is a rectangle The two number represents the length and the width. To find the perimeter we add all the lengths and the widths. Since the pool table is a rectangle we have two lengths and two widths.
So,
the tow numbers be 10 and 5. 5 is half of 10 and, when multiplied by 2 it is 10. So just to make sure the numbers 5 and 10 work out lets do a calculation.
So,
10+5+10+5 = 30feet. This proves that the sides are these two numbers.
Answer:
(x+3)(x-5)
Step-by-step explanation:
find two multiples of -15 that when added together create -2
those two numbers would be -5 and +3
-5x3=-15
-5+3=-2