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Viefleur [7K]
3 years ago
12

If eight times a number is subtracted from eleventimes the number,the result is -9.find the number.

Mathematics
2 answers:
Talja [164]3 years ago
6 0
The answer is n=3 when n= a number
CaHeK987 [17]3 years ago
4 0
So this question can be representd by

eight times a number, (8x), is subtracted from (-8x) eleven times a number (11x), the result is -9

so -8x+11x=-9 or
11x-8x=-9
add like terms
3x=-9
divide both sides by 3
x=-3
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The value of a certain car decreases by 16% each year. What is the 1⁄2-life of the car?
svet-max [94.6K]

Answer:

The half life of the car is 3.98 years.

Step-by-step explanation:

The value of the car after t years is given by the following equation:

V(t) = V(0)(1-r)^{t}

In which V(0) is the initial value and r is the constant decay rate, as a decimal.

The value of a certain car decreases by 16% each year.

This means that r = 0.16

So

V(t) = V(0)(1-r)^{t}

V(t) = V(0)(1-0.16)^{t}

V(t) = V(0)(0.84)^{t}

What is the 1⁄2-life of the car?

This is t for which V(t) = 0.5V(0). So

V(t) = V(0)(0.84)^{t}

0.5V(0) = V(0)(0.84)^{t}

(0.84)^{t} = 0.5

\log{(0.84)^{t}} = \log{0.5}

t\log{0.84} = \log{0.5}

t = \frac{\log{0.5}}{\log{0.84}}

t = 3.98

The half life of the car is 3.98 years.

7 0
3 years ago
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Listed below are speeds (mi/h) measured from southbound traffic on I-280 near Cupertino, California (based on data from SigAlert
adell [148]

Answer:

Option (B) is the correct answer to the following question.

Step-by-step explanation:

Step-1: We have to find the Mean of the series.

The series is Given in the question 62 61 61 57 61 54 59 58 59 69 60 67.

Mean(\overline{x})=\frac{62+61+61+57+61+54+59+58+59+69+60+67}{12} = 60.67

Step-2: We have to find the Standard Deviation.

Let Standard Deviation be x.

Formula of Standard Deviation is: s= \sqrt{\frac{\sum(x_{i}+\overline{x})}{n-1}}

Put value in formula of Standard Deviation,

s= \sqrt{\frac{(62+60.67)^{2}+(61+60.67)^{2}+(61+60.67)^{2}+(57+60.67)^{2}+....(67+60.67)^{2}}{n-1}} = 40.75

Step-3: Then, we have to find the critical value by chi-square.

X_{1-\alpha/2}^{2}=3.82

X_{1-\alpha/2}^{2}=21.92

Then, find the confidence interval which is 95%.

\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{21.92}.(4.075)^2 }\approx2.8868 \\ i.e 2.9

\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{3.816}.(4.075)^2 }\approx6.9188 \\ i.e 6.9

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You answer would be X=-4 
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