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Makovka662 [10]

3 years ago

14

Dean used a triple beam balance to find that the mass of a rock was 40 g and he used a graduate cylinder that measures the volum

e is 5 ml. What is the density?
a
9 m/l
b
10 g/ml
c
6 g/ml
d
8 g/ml

PLSSSSSSSSSSSSSSSSSSS HELP MEEEEEEEEEEEEEEEEE

1 answer:

zhenek [66]3 years ago

4 0

Answer:

Never bwa hahaha JK try d

Step-by-step explanation:

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Which statement about the zeros of the graphed function is true?

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A. The function has three distinct real zeros.

Step-by-step explanation:

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What is 37 more than t

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2. Use the following picture for this question:

Art [367]

Answer:

a. $24\sqrt{3}$ and 41.6

b. 52.1

Step-by-step explanation:

a.

Considering the left side triangle the blue dotted side is the side "opposite" to the angle given and the side 24 is the side that is "adjacent" to the angle given. The trigonometric ratio tan relates opposite to adjacent. Also, let the blue dotted side be y.

<u>Note:</u> the exact value of tan 60 is $\sqrt{3}$

Thus, we can write $Tan(60)=\frac{y}{24}\\y=24*Tan(60)\\y=24*\sqrt{3} \\y=24\sqrt{3}$

Approximate value (rounded to nearest tenth): $24\sqrt{3} =41.6$

b.

Considering the triangle to the right, the side "opposite" to the angle given (53 degrees) is 41.6 (just found in part (a)) and the side "hypotenuse" (side opposite to 90 degree angle) is x. The trigonometric ratio sine relates opposite and hypotenuse.

Thus we can write and solve:

$Sin(53)=\frac{41.6}{x}\\x=\frac{41.6}{Sin(53)}=52.1$

4 0

3 years ago

(1 point) Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference betw

slavikrds [6]

Answer:

a. $\frac{dT}{dt}=k(T-Tm); T(0)=190$

b. $C_{0}=122$

c. $k=-0.00259$

d. $t=153.39838\\$ minutos

Step-by-step explanation:

a. Newton's law of cooling states that the speed with which a body is cooled is proportional to the difference between its temperature and that of the medium in which it is found. Then, the initial value problem is given by:

$Tm=68$

$\frac{dT}{dt}=k(T-Tm); T(0)=190$

b. The differential equation obtained is a differential equation of separable variables:

$\frac{dT}{T-Tm}=kdt\\\\\int {\frac{dT}{T-Tm}}=\int{kdt}\\\\Ln|T-Tm|=kt+C\\\\T(t)=C_{0}e^{kt}+Tm=C_{0}e^{kt}+68\\\\T(0)=C_{0}e^{k(0)}+68=190\\\\C_{0}=122$

c. After 33 minutes of serving the coffee has cooled to 180°:

$T(33)=122e^{33k}+68=180\\\\e^{33k}=\frac{112}{122}\\\\33k=Ln(\frac{112}{122})\\\\k=-0.00259$

d.

$150=122e^{-0.00259t}+68\\\\Ln(\frac{150-68}{122})=-0.00259t\\\\t=153.39838\\\\$

8 0

3 years ago