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2 years ago

12

The distance that an automobile travels varies directly as the time it travels. If the car travels 280 miles in 7 hours, how far

will it travel in 12 hours?
answers could be either
1960
480
84
25

1 answer:

rusak2 [61]2 years ago

8 0

280 divided by 7 equals 40 and forty times 12 equals 480 so the answer is 480

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2 years ago

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A. There is a positive correlation between the temperature and the amount of ice cream sold. This means that as the temperature increases the amount of ice cream also increases.

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2 years ago

HALPPPPPPPPPPPPP<br><br>which choice shows the values from least to greatest?

KiRa [710]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

If two objects travel through space along two different curves, it’s often important to know whether they will collide. (Will a

galina1969 [7]

Answer:

<em>Both objects collide at t=3 in the point <9,9,9></em>

Step-by-step explanation:

<em>Collision Of Moving Objects </em>

Two objects can describe different trajectories in the space. Those trajectories can intersect in one or more points but it doesn't mean they collide. Collision occurs if they are in the same position at the same time. If we know the positions as a function of time of each object, we could try so find if, for a given time, they are in the same position.

The positions of two object are given as

$r1(t)=$

$r2(t)=$

Let's find out if there is at least one value of t that makes both positions to be the same. We can try by equating one of the three coordinates and testing if the value of t make both have the same x,y,z coordinate. Let's try equating the x-components of both

$t^2=4t-3$

Rearranging

$t^2-4t+3=0$

Factoring

$(t-1)(t-3)=0$

We found two solutions

$t=1,\ t=3$

for t=1 the x-coordinates are

$x1=t^2=1$

$x2=4t-3=1$

For t=3

$x1=t^2=9$

$x2=4t-3=9$

Now we'll test both values in the y-coordinates

$y1=7t-12$

$y2=t^2$

For t=1

$y1=-5$

$y2=1$

Thus they don't collide at t=1. Let's try t=3

$y1=7(3)-12=9$

$y2=3^2=9$

Now let's try the z-coordinate for t=3

$z1=t^2=9$

$z2=5t-6=9$

Since the three coordinates match, we can say both objects collide at t=3 in the point <9,9,9>

6 0

3 years ago