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kipiarov [429]
3 years ago
12

The distance that an automobile travels varies directly as the time it travels. If the car travels 280 miles in 7 hours, how far

will it travel in 12 hours?
answers could be either
1960
480
84
25
Mathematics
1 answer:
rusak2 [61]3 years ago
8 0
280 divided by 7 equals 40 and forty times 12 equals 480 so the answer is 480
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Given vectors u = (-3, 2) and v = (2, 1), what is the measure of the angle between the vectors?
BaLLatris [955]

Answer:

C) 119.7°

Step-by-step explanation:

got it right on edge :)

3 0
3 years ago
Read 2 more answers
What is the slope of the line through the points (-2, -1) and (4, 3)? ​
Natalka [10]

Answer:

#2 option: \frac{2}{3}

Step-by-step explanation:

slope=\frac{rise}{run} =\frac{y^2-y^1}{x^2-x^1}

\frac{3-(-1)}{4-(-2)}=\frac{-4}{-6} =\frac{-2}{-3} =\frac{2}{3}

=  \frac{2}{3}

8 0
2 years ago
How do I do this qn?
denis-greek [22]
You can take the log of the left and right hand side, and then apply the <span>logarithm rules:

log(a</span>ˣ) = x·log(a)
log(ab) = log(a) + log(b)

log(9^(x-1) * 2^(2x+2)) = log(6^(3x))
log(9^(x-1)) + log(2^(2x+2)) = 3x log(6)
(x-1) log(9) + (2x+2) log(2) - 3x log(6) = 0
x(log9 + 2log2 - 3log6) = log9 - 2log2
x = (log9 - 2log2) / (log9 + 2log2 - 3log6)

simplifying by writing log9 = 2log3 and log6 = log2+log3

x= 2(log3 - log2) / (2log3 + 2log2 - 3log2 - 3log3) = 
x= -2(log3 - log2) / (log3 + log2) = -2 log(3/2) / log(6)

So 6^x = 4/9
3 0
4 years ago
How do I solve this problem
DaniilM [7]

Answer:

trrtrtrtrtrtrtrtrt

Step-by-step explanation:


6 0
3 years ago
Please help me I need help please​
MakcuM [25]

Answer:

p = 4

Step-by-step explanation:

Given equation:

x^2+(p-3)y^2-4x+6y-16=0

<u>Standard equation of a circle:</u>

(x-a)^2+(y-b)^2=r^2

(where (a,b) is the centre of the circle, and r is the radius)

If you expand this equation, you will see that the coefficient of y^2 is always one.

Therefore, p-3=1

\implies p=1+3=4

<u>Additional information</u>

To rewrite the given equation in the standard form:

\implies x^2+y^2-4x+6y-16=0

\implies x^2-4x+y^2+6y=16

\implies (x-2)^2-4+(y+3)^2-9=16

\implies (x-2)^2+(y+3)^2=16+4+9

\implies (x-2)^2+(y+3)^2=29

So this is a circle with centre (2, -3) and radius √29

3 0
2 years ago
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