Answer:
80 hours. 2,000 ÷ 25 = 80
Answer: 530 hours
Explanation:
The reduction of Nickel ions to nickel is shown as:
of electricity deposits 1 mole of Nickel
1 mole of Nickel weighs = 58.7 g
Given quantity = 18.0 kg = 18000 g (1kg=1000g)
58.7 g of Nickel is deposited by 193000 C of electricity
18000 g of Nickel is deposited by = of electricity
where Q= quantity of electricity in coloumbs = 59182282.8C
I = current in amperes = 31.0 A
t= time in seconds = ?
(1h=3600 sec)
Thus 530 hours are required to plate 18.0 kg of nickel onto the cathode if the current passed through the cell is held constant at 31.0 A
1) Answer is: the hydrogen ion concentration is 1·10⁻¹ mol/L.
[OH⁻] = 1·10⁻¹³<span> mol/L, equilibrium concentration of hydroxide anion.
</span>[H⁺] is the concentration<span> of hydrogen ions.
</span>[OH⁻] · [H⁺] = 10⁻¹⁴ mol²/L², ionicproduct of water on room temperature.
[H⁺] = 10⁻¹⁴ mol²/L² ÷ 1·10⁻¹³ mol/L.
[H⁺] = 10⁻¹ mol/L = 0,1 mol/L.
2) pH = -log[H⁺], <span>approximately </span><span>the negative of the base 10 </span>logarithm<span> of the </span>molar concentration of hydrogen ions
pH = -log(10⁻¹ mol/L).
pH = 1.
This solution is acid, because pH value (potential of hydrogen) is less than seven. If pH is greater than seven, slotion is base and if pH is equal seven, solution is neutral.
to separate an ionic compound into its individual ions
Answer:
To balance the reaction, we should put a 4 in front of Al
Explanation:
<u>Step 1:</u> Data given
AI+3O2->2AI2O3
<u>Step 2:</u> Balance the equation
On the right side we have 2*3 = 6 oxygen atoms
On the left side we have 3*2 = 6 oxygen atoms as well, so those are on both side balanced
On the right side we have 2*2 = 4 Al atoms
On the left side we have only 1 Al atom
We should multiply this by 4 (place a 4 in front of the Al)
4AI + 3O2 → 2AI2O3
Now al atoms are balanced on both sides.