Na2CO3 mol = mass/rfm
= 91.9 / ( 23+23+12+16+16+16)
= 91.9/106
=919/1060 or roughly 0.867
Mole ratio of sodium carbonate to calcium carbonate is 1:1
Therefore calcium carbonate mol = mass/rfm
919/1060 = mass / (40+12+16+16+16)
919/1060 = mass / 100
Mass = 919/1060 x 100
= 4595/53 or 86.7g to 3 significant figures
1.63 moles since 1 mole is equal to 136.4332 grams
According to given chemical reaction, one mole of carbon monoxide reacts with one mole of water results in the formation of one mole of calcium hydroxide.
Therefore, calcium monoxide and water reacts in one ratio one (1:1).
Now, in given chemical reaction, change in enthalpy is negative i.e. -65.2 kJ (less than zero).
The negative sign of change is enthalpy indicates that heat is released and the reaction in which heat is released is said to be exothermic reaction. Thus, the given reaction is exothermic i.e. heat is released.
Hence, 65.2 kJ of heat is released for every one mole of calcium monoxide which reacts is the correct statement for the given reaction.
The type of reaction that involved the transfer of electrons is oxidation-reduction
