The answer is tree hope this helped :)
Answer:
The correct answer would be 10.
The cell cycle can be divided into four phases namely gap 1 (G₁) phase , synthesis (S) phase, gap 2 (G₂) phase, and mitosis (M) phase.
DNA (deoxyribonuceic acid) content is only replicated and doubled in the S phase. However, the chromosome number remains the same. It can be explained as the number of chromosomes remains the same (2n) but number of chromatids doubles (4n) after S phase.
The number of chromatids restores to 2n in daughter cells after completion of mitosis.
Hence, if number of chromatids in metaphase was 20 i.e. 4n then the number of chromosomes (2n) would be 10.
Hence, 10 chromosomes or 5 pairs of chromosome would be present in the cell during its G₁ phase.
Answer:
38 ATP
Explanation:
On complete oxidation of one molecule of glucose yields 38 ATP. Break up of energy production is given below:
- During glycolysis 2 ATP and 2 NADH is produced.
- During formation of Acetyl CoA, 2 NADH is produced.
- During Citric Acid Cycle, 2 ATP, 6 NADH, 2 FADH₂ are produced.
Finally during Electron transport chain, reduced coenzymes NADH and FADH₂ oxidised to release ATP. Each NADH produce 3ATP and each FADH₂ produces 2 ATP. Altogether 10 NADH is produced during entire process of cellular respiration which yield 30 ATP and 2 FADH₂ yields 4 ATP. Therefore, on complete oxidation of one molecule of glucose yields 38 ATP.