All categories

3 years ago

What expression is equal to 75. Squared?

Mathematics

1 answer:

Murljashka [212]3 years ago

8 0

The answer to 75 squared is 5,625.

You might be interested in

Wanna show y'all the thiccc hamster !

34kurt

Answer:

oop

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Find the value of x. Round to the nearest tenth. 37 17.3 units

dlinn [17]

Answer:

x ≈ 21.7

I rounded to the nearest tenth because the values are given in tenths. The first few digits of x are below if you are rounding to something else, as the image is cut out.

Step-by-step explanation:

(It will not let me post, so I've attached a screenshot of my explanation:)

7 0

2 years ago

HERE IS FREE POINTS AND SUBSCRIBE TO SHADICAL_RR ON YT

ZanzabumX [31]

Answer:

Why Just why

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

If 5 dozen roses can be purchased for $62.50, how much will 8 dozen cost?

lesya692 [45]

Source: Net

Let x represent the cost of a dozen roses. 5 dozen roses can be purchased for $62.50 . Consider the following equation. 5x = $62.50. Here the product and factor are known, thus divide by the factor on both sides of the equation.

5x $62.50

-- = --

5 $12.50

Now to find out the cost of 8 dozens multiply the value of x by 8.

8x=8 ($12.50) = $100

Answer would be $100.

5 0

2 years ago

Read 2 more answers

Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5

givi [52]

<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

$A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]$ $X=\left[\begin{array}{c}x\\y\end{array}\right]$

and $B= \left[\begin{array}{c}11\\5\end{array}\right]$

∴AX=B

$adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]$

$A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6$

∴ $A^{-1} =\frac{adj A}{|A|}$

So, $A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}$

$A^{-1} ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}$

$X =A^{-1}\times B$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c} {6}\\ {11} \end{array}\right]}$

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0

2 years ago