Answer:
Domain: {-3, -1, 1}
Range: {-1, 2, 4, 5}
Step-by-step explanation:
The domain of given function is <u>All real numbers</u>
For each value of x the function is defined.
Example -
The value is 
The value is 4
The scale factor that Thea uses to go from Rectangle Q to Rectangle R is equal to 6.
<h3>What is the scale factor from rectangle Q to rectangle R?</h3>
In geometry, the scale factor is a ratio of the resulting length to the initial length. Since the area of the square is equal to the square of its side length, then the scale factor is equal to:
k² = A' / A
k = √(A' / A)
Where:
- k - Scale factor
- A' - Area of the rectangle R.
- A - Area of the rectangle Q.
If we know that A = 2 and A' = 72, then the scale factor is:
k = √(72 / 2)
k = √36
k = 6
Then, the scale factor that Thea uses to go from Rectangle Q to Rectangle R is equal to 6.
To learn more on scale factors: brainly.com/question/22312172
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3/4 times x=2
times both sides by 4/3 to clear fraction (4/3 times 3/4=12/12=1)
1x=8/3
there are 8/3 of them in 2
Answer:
y = -2x - 10
Step-by-step explanation:
Slope intercept form of equation is of form
y = mx+c
where m is the slope of line and c is the y intercept of the line.
Y intercept is point on y axis where the line intersects the y axis.
_____________________________
Given equation
y = -2x +4
comparing it with y = mx+ c
m = -2 , c = 4
_____________________________
when two lines are parallel, their slopes are equal.
Let the equation of new line in slope intercept form be y = mx + c
Thus slope of of new required line is -2
Thus m for new line is -2.
now, equation of required line : y = -2x+c
Given that this line passes through (-4, -2). This point shall should satisfy equation y = -2x+c.
Substituting the value of (-4, -2) we have
-2 = -2(-4)+c
=> -2 = 8 +c
=> -2 -8 = c
=> c = -10.
Thus , equation of required line is y = -2x - 10.
