Hi,
what is the area, in square inches, of the largest triangle that can fit into a 3-inch by 4-inch rectangle. please show how you
got your answer:)
1 answer:
The area of the largest triangle would be 6 inches².
How did I get this? I'll explain first:
We would want our triangle to have the longest sides, so it can be big. If you think of a rectangle, a triangle can fit into it if:
The base (bottom) of the triangle is the same length as one side of the rectangle, and the other side of the triangle is perpendicular (90°) to the bottom and is the same length of the other side of the rectangle.
Okay, just picture it: two sides of the triangle are resting in the two sides of the rectangle, and the third side of the triangle is a line that splits the rectangle in half from one corner to the other.
I've added an image to explain.
The formula to find the area of a triangle is half of the base × height.
A of Δ = half of 3 × 4
A = 1.5 × 4 = 6 inches²!
How did I get this? I'll explain first:
We would want our triangle to have the longest sides, so it can be big. If you think of a rectangle, a triangle can fit into it if:
The base (bottom) of the triangle is the same length as one side of the rectangle, and the other side of the triangle is perpendicular (90°) to the bottom and is the same length of the other side of the rectangle.
Okay, just picture it: two sides of the triangle are resting in the two sides of the rectangle, and the third side of the triangle is a line that splits the rectangle in half from one corner to the other.
I've added an image to explain.
The formula to find the area of a triangle is half of the base × height.
A of Δ = half of 3 × 4
A = 1.5 × 4 = 6 inches²!
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Answer: Choice C
Vertex = (5, -2)
===============================================
Explanation:
Vertex form is where the vertex itself is located at (h,k)
As the name implies, we can very quickly pull out the coordinates of the vertex without doing much math at all.
In the case of choice C, we have which is the same as
and we can see that h = 5 and k = -2. Therefore, the vertex is located at (h,k) = (5, -2)