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lesantik [10]
3 years ago
6

what is the area, in square inches, of the largest triangle that can fit into a 3-inch by 4-inch rectangle. please show how you

got your answer:)

Mathematics
1 answer:
AnnyKZ [126]3 years ago
4 0
The area of the largest triangle would be 6 inches².

How did I get this? I'll explain first:

We would want our triangle to have the longest sides, so it can be big. If you think of a rectangle, a triangle can fit into it if:

The base (bottom) of the triangle is the same length as one side of the rectangle, and the other side of the triangle is perpendicular (90°) to the bottom and is the same length of the other side of the rectangle.

Okay, just picture it: two sides of the triangle are resting in the two sides of the rectangle, and the third side of the triangle is a line that splits the rectangle in half from one corner to the other.

I've added an image to explain.

The formula to find the area of a triangle is half of the base × height.

A of Δ = half of 3 × 4
A = 1.5 × 4 = 6 inches²!

You might be interested in
Suppose researchers test 100 college students, whose ages range from 18 to 23. They also test 100 people at a nearby community c
prisoha [69]

Answer:

b. You would conclude that the differences in the average scores can be traced to differences in the working memory of the two groups.

Step-by-step explanation:

Though the average scores of the two sets could have lead to various conditions, but retentive ability deminishes with respect to an increase in age. With respect to the age of the elderly people involved, it is expected that some of them would not be able to retain information for a long period of time. Thus, their average score is 72%.

The college students' are younger, so it is expected that they should be able to retain more information. That ability is one of the reasons why their average score is 85%.

It can be concluded from the research that the differences in the average scores is probably due to the working memory of the two groups.

6 0
3 years ago
Consider this scenario: The population of a city increased steadily over a ten-year span. The following ordered pairs show the p
vova2212 [387]

Answer:

Regression function: y=1986.406+0.0059x

The function predicts that population will reach 14,000 in year 2068.

Step-by-step explanation:

We have to determine a function y=b_0+b_1x_1 by applying linear regression. The data we have is 5 pair of points which relates population to year.

According to the simple regression model (one independent variable), if we minimize the error between the model (the linear function) and the points given, the parameters are:

b_0=\bar{y}+b_1\bar{x}\\\\b_1=\frac{\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}}{\sum\limits^5_{i=1} {(x_i-\bar x)^2}}

We start calculating the average of x and y

\bar x=\frac{2500+2650+3000+3500+4200}{5}=\frac{15850}{5}=3170\\\\ \bar y=\frac{2001+2002+2004+2007+2011}{5}=\frac{10025}{5}=2005

The sample covariance can be calculated as

\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}=(2500-3170)(2001-2005)+(2650-3170)(2002-2005)+(3000-3170)(2004-2005)+(3500-3170)(2007-2005)+(4200-3170)(2011-2005)\\\\\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}=2680+1560+170+660+6180\\\\ \sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}=11250

The variance of x can be calculated as

\sum\limits^5_{i=1} {(x_i-\bar x)^2}=(2500-3170)^2+(2650-3170)^2+(3000-3170)^2+(3500-3170)^2+(4200-3170)^2\\\\\sum\limits^5_{i=1} {(x_i-\bar x)^2}=448900+270400+28900+108900+1060900\\\\\sum\limits^5_{i=1} {(x_i-\bar x)^2}=1918000

Now we can calculate the parameters of the regression model

b_1=\frac{\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}}{\sum\limits^5_{i=1} {(x_i-\bar x)^2}}=\frac{11250}{1918000}=0.005865485  \\\\ b_0=\bar{y}+b_1\bar{x}=2005-0.005865485*3170=1986.406413

The function then become:

y=1986.406+0.0059x

With this linear equation we can predict when the population will reach 14,000:

y=1986.406+0.0059(14,000)=1986.406+82.117=2068.523

6 0
3 years ago
A house is 25 feet tall and a ladder is set up 35 feet away from the side of the house. approximately how long is the ladder fro
maks197457 [2]
Use Pythagorean Theorem of a^2 + b^2 = c^2 where a and b are the legs of the triangle set up by the house height and the ground, and c is the hypotenuse or how long the ladder is. C is going to be our unknown.
 
Just plugging in you get 25^2 + 35^2 = c^2. Simplify to 625 + 1225 = c^2. Simplify again to 1850 = c^2. The square root both sides to isolate the variable c. C = sqrt(1850) or approximately 43.0116 feet if rounded to 4 decimal places. 

The ladder is approximately 43.0116 feet long. 
4 0
3 years ago
George and veronica are both musicians who sell their sogn online during the same year George sold 8x10^5 download of his song a
anygoal [31]

George sold:

\begin{gathered} 8\times10^5 \\ =800,000 \end{gathered}

and Veronica sold:

\begin{gathered} 4\times10^6 \\ =4,000,000 \end{gathered}

As expanding the scientific notation numbers, we see that

George sold eight hundred thousand

Veronica sold 4 million

How many time is 4 million of 8 hundred thousand?

We simply divide!

\frac{4,000,000}{800,000}=5

So,

Veronica's song was downloaded 5 times the numebr of that of George.

B is the right answer.

5 0
1 year ago
Beatrice calculated the slope between two pairs of points.
kumpel [21]

Answer:

The answer in the procedure

Step-by-step explanation:

we know that

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

step 1

Find the slope between (-3, -2) and (1, 0)

m=\frac{0+2}{1+3}

m=\frac{2}{4}=\frac{1}{2}

Find the equation of the line

y-y1=m(x-x1)

with m and the point (1,0)

substitute

y-0=\frac{1}{2}(x-1)

y=\frac{1}{2}x-\frac{1}{2}

step 2

Find the slope between (-2, -1) and (4, 2)

m=\frac{2+1}{4+2}

m=\frac{3}{6}=\frac{1}{2}

Find the equation of the line

y-y1=m(x-x1)

with m and the point (4,2)

substitute

y-2=\frac{1}{2}(x-4)

y=\frac{1}{2}x-2+2

y=\frac{1}{2}x

<em>Compare the equation of the two lines</em>

The two lines are parallel, because their slope is the same, but are different lines

therefore

Beatrice's conclusion is incorrect

All of these points are not on the same line, because are different parallel lines

The slope between (-2,-1) and (1,0) is equal to \frac{1}{2}

8 0
4 years ago
Read 2 more answers
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