The dot plot with the least number of sites has the least frequency
The dot plot has the least number of sites is the Shield Darter
<h3>How to determine the dot plot?</h3>
To determine the dot plot with the least number of sites, we simply calculate the total frequency of each dot plot
So, we have:
Shield Darter = 3 + 1 + 4 + 2 + 3 + 1 + 1
Shield Darter = 15
Calico Crayfish = 1 + 1 + 3 + 4 + 1 + 2 + 4 + 2
Calico Crayfish = 18
Zebra Mussel = 1 + 3 + 2 + 5 + 1 + 1 + 2 + 3 + 2
Zebra Mussel = 20
Blue back Herring = 3 + 3 + 2 + 1 + 3 + 1 + 4
Blue back Herring = 17
From the computation above, the least frequency is
Shield Darter = 15
Hence, the dot plot has the least number of sites is the Shield Darter
Read more about dot plots at:
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The decay factor for the annual rate of change of - 55 % is 0.45.
A quantity must vary by a specific percentage each time period in order for growth or decay to be exponential.
With the function displayed to the right, you may represent exponential growth or decay.
A(x) = a( 1 + r)ˣ
Where A is the amount after x time periods, a is the initial amount, x is the number of time periods, and r is the rate of change.
Now, we have the annual rate of change as:
r = - 55 % = - 55 / 100 = - 0.55
From the function A(x) = a( 1 + r)ˣ , the corresponding factor is 1 + r.
So, let B = 1 + r
B = 1 + r
B = 1 + (- 0.55)
B = 1 - 0.55
B = 0.45
Now, the value of B is less than 1 therefore, the corresponding decay factor is 0.45.
Learn more about growth and decay factor here:
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Answer:
the answer is y=8x+42
Step-by-step explanation:
y-y=m(x-x¹)
y-2=8(x-(-5))
y-2=8x+40
+2 +2
y=8x+42
Answer:
52500
Step-by-step explanation:
