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3 years ago

Find the volume of this composite figure and explain how you got your answer

Mathematics

1 answer:

Damm [24]3 years ago

7 0

To solve this, we work out the volume of the two shapes (the cuboid and the pyramid) and then add them together.

We get the volume of the cuboid by multiplying the base by the width by the length:

Volume of cuboid = 6 x 6 x 4
= 144m³

Now to get the volume of the pyramid, we multiply the base by the length by the height, and then we divide by three.

Volume of pyramid = 6 x 6 x 8 ÷ 3
= 96m³
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Answer:
Now that we know the two volumes, we simply add them together:

144 + 96 = 240m³

So the volume of the composite sold is 240m³

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PLEASE I NEED HELP! THANK YOU.

Elden [556K]

First set up a linear equation and using the x and y values in the table see if it solves.

It doesn't solve so we know it isn't linear. ( I won't show all those steps because they aren't needed.)

Using the quadratic formula y = ax^2 +bx +c

Build a set of 3 equations from the table:

C is the Y intercept ( when X is 0), this is shown in the table as 6

Now we have y = ax^2 + bx + 6

-2.4 =4a-2b +6

1.4 = a-b +6

Rewrite the equations

a=b/2 -2.1

1.4 = b/2-2.1 +6

b = 5

a = 5/2 -2.1 = 0.4

replace the letters to get y = 0.4x^2 + 5x +6

4 0

3 years ago

A half-century ago, the mean height of women in a particular country in their 20s was 64.7 inches. Assume that the heights of

Ainat [17]

Answer:

99.5% of all samples of 21 of today's women in their 20's have mean heights of at least 65.86 inches.

Step-by-step explanation:

We are given that a half-century ago, the mean height of women in a particular country in their 20's was 64.7 inches. Assume that the heights of today's women in their 20's are approximately normally distributed with a standard deviation of 2.07 inches.

Also, a samples of 21 of today's women in their 20's have been taken.

Let $\bar X$ = sample mean heights

The z-score probability distribution for sample mean is given by;

Z = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean height of women = 64.7 inches

$\sigma$ = standard deviation = 2.07 inches

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample of 21 of today's women in their 20's have mean heights of at least 65.86 inches is given by = P( $\bar X$ $\geq$ 65.86 inches)

P( $\bar X$ $\geq$ 65.86 inches) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ $\geq$ $\frac{65.86-64.7}{\frac{2.07}{\sqrt{21} } }$ ) = P(Z $\geq$ -2.57) = P(Z $\leq$ 2.57)

= 0.99492 or 99.5%

The above probability is calculated by looking at the value of x = 2.57 in the z table which has an area of 0.99492.

Therefore, 99.5% of all samples of 21 of today's women in their 20's have mean heights of at least 65.86 inches.

3 0

3 years ago

4 Riley finds a recipe for bubble solution that uses 1 cup water, 2 cup dish soap,

Arada [10]

Answer:

1 cup

Step-by-step explanation:

the recipe calls for one cup of water per two cups of dish soap, so if she uses two cups of dish soap she should use one cup of water and one tablespoon of corn syrup.

4 0

3 years ago

Solve If QR = 6x + 1, PR = 14x - 13, and PQ = 5x - 2, find PR

solong [7]

Answer:

P____Q____R

PR= PQ+ QR

(14x-13) = (5x-2)+(6x+1)

14x-13= 11x – 1

14x – 11x = 13–1

3x = 12

x= 12/ 3

x= 4

PR= 14x – 13 = 14 (4) – 13 = 18 – 13= 5

If you want (PQ , QR ) this is the solution

PQ =5x-2=5(4)-2=20-2=18

QR =6x+1=6(4)+1=24+1=25

I hope I helped you^_^

7 0

3 years ago

Find the circumference of the circle shown below if the diameter equals 20 inches. Use 3.14 for π

Tanzania [10]

Answer:

62.8 inches

Step-by-step explanation:

c = πd

c = 3.14 * 20

c = 62.8 inches

4 0

3 years ago