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3 years ago

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A batch of snack mix made of dried fruit and nuts contain 744G of nuts the ratio of nuts to dried fruit by weight is 12 to 13 ho

w much does a batch of snack mix way?

1 answer:

Bezzdna [24]3 years ago

6 0

In a bag of snack mix:

n = nuts d = dried fruit

n = 744g d = ???g

Ratio Nuts/Dried fruit = 12/13

This basically means that if the mix was divided in 25 parts, 12 parts would be nuts and 13 would be dried fruits

If 744 is 12 parts then 744/12 is 1 part

744/12 = 62

1 part = 62g

there are 13 parts of dried fruit

13 x 62 = 806

744g of nuts + 806g of dreid fruit = 1550g

Answer: A batch of snack mix weigh 1550g, or 1.55kg

hope it helps :)

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A butterfly starts at 20 m and changes -16m ?

miskamm [114]

Answer:

it is at 4 meters

Step-by-step explanation:

20 - 16 = 4

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3 years ago

professor wrote the following inequalities for N number of students in his lecture. N <10, N>10, N<22, N>22. Turns o

m_a_m_a [10]

Answer:

There are N students in the class.

We know that ONLY ONE of the inequalities is true:

N < 10

N > 10

N < 22

N > 22

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Remember that if we have:

x > y

y is not a solution, because:

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Then:

If we take N = 10, then:

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8 0

3 years ago

At 10 percent interest, how long does it take to quadruple your money?

horsena [70]

It takes about 14.55 years for quadruple your money

<em><u>Solution:</u></em>

Given that,

At 10 percent interest, how long does it take to quadruple your money

Rule of 144:

The Rule of 144 will tell you how long it will take an investment to quadruple

Here,

Rate of interest = 10 %

Therefore, number of years to quadruple your money is obtained by dividing 144 by 10

<em><u>Rule of 144 Formula: </u></em>

$N = \frac{144}{R}$

Where:

N = Number of many years times.

144 = Is the constant variable.

R = Rate of interest.

$\rightarrow N = \frac{144}{10} = 14.4$

Thus it takes about 14.4 years for quadruple your money.

<em><u>Another method:</u></em>

If initial amount is $ 1 and it if quadruples it should be $ 4

We have to find the number of years if rate of interest is 10 %

Let "n" be the number of years

Then we can say,

$Amount = Principal(1+\frac{R}{100})^n$

$4 = 1(1+\frac{10}{100})^n$

$4 = 1(1+0.1)^n\\\\4= 1(1.1)^n\\\\4 = 1.1^n\\\\We\ know\ that,\\\\(1.1)^{14.55} = 1.1^n\\\\We\ know\ that\\\\If\ a^m = a^n\ then\ m = n\\\\Therefore,\\\\14.55 = n\\\\n = 14.55$

Thus Option D 14.55 years is correct

7 0

3 years ago

Two shooters, Rodney and Philip, practice at a shooting range. They fire rounds each at separate targets. The targets are mark

Sedaia [141]

Complete Question

Answer:

a

$SE = 0.66}$

b

$-3.29 < \mu_1 - \mu_2 < -0.70$

Step-by-step explanation:

From the question we are told that

The sample size is n = 60

The first sample mean is $\= x _1 = 8$

The second sample mean is $\= x _2 = 10$

The first variance is $v_1 = 0.25$

The first variance is $v_2 = 0.55$

Given that the confidence level is 95% then the level of significance is 5% = 0.05

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the first standard deviation is

$\sigma_1 = \sqrt{v_1}$

=> $\sigma_1 = \sqrt{0.25}$

=> $\sigma_1 = 0.5$

Generally the second standard deviation is

$\sigma_2 = \sqrt{v_2}$

=> $\sigma_2 = \sqrt{0.55}$

=> $\sigma_2 = 0.742$

Generally the first standard error is

$SE_1 = \frac{\sigma_1}{\sqrt{n} }$

$SE_1 = \frac{0.5}{\sqrt{60} }$

$SE_1 = 0.06$

Generally the second standard error is

$SE_2 = \frac{\sigma_2}{\sqrt{n} }$

$SE_2 = \frac{0.742}{\sqrt{60} }$

$SE_2 = 0.09$

Generally the standard error of the difference between their mean scores is mathematically represented as

$SE = \sqrt{SE_1^2 + SE_2^2 }$

=> $SE = \sqrt{0.06^2 +0.09^2 }$

=> $SE = 0.66}$

Generally 95% confidence interval is mathematically represented as

$(\= x_1 -\= x_2) -(Z_{\frac{\alpha }{2} } * SE) < \mu_1 - \mu_2 < (\= x_1 -\= x_2) +(Z_{\frac{\alpha }{2} } * SE)$

=> $(8 -10) -(1.96 * 0.66) < \mu_1 - \mu_2 < (8-10) +(Z_{\frac{\alpha }{2} } * 0.66)$

=> $-3.29 < \mu_1 - \mu_2 < -0.70$

5 0

3 years ago

Please help im desperate. :)

Serhud [2]

D - 6lb / $1 would be the answer

8 0

2 years ago