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LenKa [72]
3 years ago
7

4 and 1/12 + 5 and 1/6 + 2 and 1/4

Mathematics
1 answer:
e-lub [12.9K]3 years ago
4 0
11 and 1/2............................................
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PLEASE help me with this question and I WILL love you forever But yeah please help me with the question.And EXPLAIN in words how
Rufina [12.5K]
Well on this problem recall area of a rectangle is defined by:

A = lw    our w = 1/6 and our l = (x + \frac{2}{3})   we have let 'x' represent our original length.
(x +  \frac{2}{3} )( \frac{1}{6} )= \frac{11}{72}
\frac{1}{6} x+ \frac{2}{18} = \frac{11}{72}
12x + 8 = 11
12x = 11 - 8
12x = 3
x = \frac{3}{12} = \frac{1}{4}  So our original length is \frac{1}{4}
5 0
4 years ago
The price of a car is £15400 before it is reduced by 8%.
Butoxors [25]

Answer:

£14,168

Step-by-step explanation:

3 0
3 years ago
Can someone please tell me what the answer is to the sentence I don't care much about the answer to the problems.
castortr0y [4]

Answer:

y = x + 12

y + x = 52

x = 20

y = 32

Step-by-step explanation:

Make a system of linear equations using x and y to represent the players on the soccer and field hockey team respectively:

y = x + 12 (this shows how many players are on the hockey team)

y + x = 52 (this shows that there are 52 players total from both teams)

Solve for the variables using either elimination or substitution:

y + x = 52

(x + 12) + x = 52

2x + 12 = 52

2x = 40

x = 20

Then plug x into the first equation:

y = x + 12

y = (20) + 12

y = 20 + 12

y = 32

8 0
3 years ago
Read 2 more answers
Plz help...............................
kupik [55]
A^5 should be your answer
7 0
3 years ago
Read 2 more answers
What is y^2-6y=0 without using quadratic formula?
boyakko [2]

y^2-6y=0\\ \\ y(y-6)=0\\ \\ y=0...and...(y-6)=0\\ \\ y=0...and...y=6

Since both y squared and 6y have a common factor of y, can put that to the side and divide both the y squared and 6y to get the second step of the work shown above. Separate both the y on the outside of the parentheses and the numbers within the parentheses and set them both equal to 0 as shown in step 3 of the work shown above. Finally solve for y as you would normally. Those two number in step 4 should be your final answer.

3 0
3 years ago
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