1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nadya [2.5K]
3 years ago
8

If angle 1 and angle 2 are adjacent angles, then do angle 1 and angle 2 form a linear pair?

Mathematics
1 answer:
Olin [163]3 years ago
8 0
Yes, if two angles are adjacent, that makes them a linear pair.
You might be interested in
PLS HELP
cricket20 [7]

Answer:

Bar graph

Step-by-step explanation:

Hopes this helps

7 0
2 years ago
Yo is someone finna do my aleks?… I only need 8topics but if u can do at least 4 that’s good enough (plz only awnser if ur willi
Lelechka [254]

Answer:

4

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Write 931 x 10-5 in standard notation.
Stella [2.4K]

Answer:

0.000093

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
For questions 13-15, Let Z1=2(cos(pi/5)+i Sin(pi/5)) And Z2=8(cos(7pi/6)+i Sin(7pi/6)). Calculate The Following Keeping Your Ans
weqwewe [10]

Answer:

Step-by-step explanation:

Given the following complex values Z₁=2(cos(π/5)+i Sin(πi/5)) And Z₂=8(cos(7π/6)+i Sin(7π/6)). We are to calculate the following complex numbers;

a) Z₁Z₂ = 2(cos(π/5)+i Sin(πi/5)) * 8(cos(7π/6)+i Sin(7π/6))

Z₁Z₂ = 18 {(cos(π/5)+i Sin(π/5))*(cos(7π/6)+i Sin(7π/6)) }

Z₁Z₂ = 18{cos(π/5)cos(7π/6) + icos(π/5)sin(7π/6)+i Sin(π/5)cos(7π/6)+i²Sin(π/5)Sin(7π/6)) }

since i² = -1

Z₁Z₂ = 18{cos(π/5)cos(7π/6) + icos(π/5)sin(7π/6)+i Sin(π/5)cos(7π/6)-Sin(π/5)Sin(7π/6)) }

Z₁Z₂ = 18{cos(π/5)cos(7π/6) -Sin(π/5)Sin(7π/6) + i(cos(π/5)sin(7π/6)+ Sin(π/5)cos(7π/6)) }

From trigonometry identity, cos(A+B) = cosAcosB - sinAsinB and  sin(A+B) = sinAcosB + cosAsinB

The equation becomes

= 18{cos(π/5+7π/6) + isin(π/5+7π/6)) }

= 18{cos((6π+35π)/30) + isin(6π+35π)/30)) }

= 18{cos((41π)/30) + isin(41π)/30)) }

b) z2 value has already been given in polar form and it is equivalent to 8(cos(7pi/6)+i Sin(7pi/6))

c) for z1/z2 = 2(cos(pi/5)+i Sin(pi/5))/8(cos(7pi/6)+i Sin(7pi/6))

let A = pi/5 and B = 7pi/6

z1/z2 = 2(cos(A)+i Sin(A))/8(cos(B)+i Sin(B))

On rationalizing we will have;

= 2(cos(A)+i Sin(A))/8(cos(B)+i Sin(B)) * 8(cos(B)-i Sin(B))/8(cos(B)-i Sin(B))

= 16{cosAcosB-icosAsinB+isinAcosB-sinAsinB}/64{cos²B+sin²B}

= 16{cosAcosB-sinAsinB-i(cosAsinB-sinAcosB)}/64{cos²B+sin²B}

From trigonometry identity; cos²B+sin²B = 1

= 16{cos(A+ B)-i(sin(A+B)}/64

=  16{cos(pi/5+ 7pi/6)-i(sin(pi/5+7pi/6)}/64

= 16{ (cos 41π/30)-isin(41π/30)}/64

Z1/Z2 = (cos 41π/30)-isin(41π/30)/4

8 0
3 years ago
I need help on my homework! i've tried a couple of times on these 3 but im confused thanks
statuscvo [17]
15/6=2.5 which is the scale factor since they are similar triangles. We divide each side of the large triangle by 2.5 to get the sides for the small triangle since they are similar. 20/2.5=8cm
25/2.5=10cm

For the second problem, you put 15/6 and set in equal to x/8 when you cross multiply you get 6x=120 then you divide x=20

For the last problem, you divide 43,75 by 5 then multiply it by 400 to get the kiloliters which equals 3,500.


4 0
2 years ago
Read 2 more answers
Other questions:
  • Explain how you can tell if the expressions 7x - 4 and 6x - 4 are equivalent using the interactive Tool?
    15·2 answers
  • A suburban high school has a population of 1376 students. The number of students who participate in sports us 649. The number of
    8·1 answer
  • 6.2 x 4.3 + 7.6 simplify
    12·1 answer
  • Which of the following expressions is equivalent to?
    7·1 answer
  • The Student Council is making six right triangular pennants to promote school spirit. Each right triangle is 9 inches high and 2
    15·2 answers
  • Help me please I really do need help tho
    7·1 answer
  • I need help fast I appreciate the help
    8·2 answers
  • What number is the arrow pointing at?​
    5·2 answers
  • Please help ill give brainliest
    6·2 answers
  • The polygons are similar. Find the missing side length. NO LINKS!!!!​
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!