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Zina [86]
3 years ago
11

PLEASE HELP!!!! An equation is written to represent the relationship between the temperature in Alaska during a snow storm, y, a

s it relates to the time in hours, x, since the storm started. A graph of the equation is created. Which quadrants of a coordinate grid should be used to display this data?
Mathematics
1 answer:
Brilliant_brown [7]3 years ago
5 0
Hi I did my email I have been
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The cost for laminating varies directly with the number of pages laminated. A customer had 19 pages laminated and paid $16.15.
strojnjashka [21]
Y=kx --- $16.15=K❎19 --- 16.15/19 =.85 --- the cost per page is 85 cents. .85x31 =$26.35 :)
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4 years ago
Consider the initial value problem 25y′′+40y′+16y=0, y(0)=a, y′(0)=−1. Find the critical value of a that separates solutions tha
Anna007 [38]

Answer:

Step-by-step explanation:

Given the differential equation

25y′′+40y′+16y=0

Using D operator to find the complementary solution

Since the Differential equation is equal to 0, then it doesn't have a partial solution.

25y′′+40y′+16y=0

25D² + 40D +16 = 0

25D² + 20D + 20D +16 = 0

5D(5D+4)+4(5D+4)= 0

(5D+4)=0 twice

D = -4/5 twice,

So the solution is a real and equal roots

y(t) = (A+B•t) exp(—0.8t)

Where A and B are constant

The initial value are.

y(0)=a, y′(0)=−1

y(0) = a = (A+B(0)) exp(—0.8(0))

a = A

Then, the constant A = a.

Now, y'(t)

y'(t)=B•exp(-0.8t)-0.8(A+B•t)exp(-0.8t

-1 = B - 0.8A

Since A =a

Then, B = 0.8a —1

The solution becomes

y(t) = (a+(0.8a-1)•t) exp(—0.8t)

For t>0

For positive,

a + (0.8a -1)> 0

1.8a > 1

a > 1/1.8

a > 10/18 > 5/9

a > 5/9.

6 0
4 years ago
WILL NAME BRAINLIST!!
Novosadov [1.4K]

Answer:

D

Step-by-step explanation:

The fourth graph makes sense, and follows Deepak's equation. To check if a graph follows an equation, all you have to do is substitute the values of x and y into the equation and see if they follow the equation.

3 0
4 years ago
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5/ 8 inch border closest to 1/ 2 or 1 inch
Triss [41]
different\ between\ \frac{5}{8}\ and\ \frac{1}{2}=\frac{5}{8}-\frac{1}{2}=\frac{5}{8}-\frac{4}{8}=\frac{1}{8}\\\\different\ between\ 1\ and\ \frac{5}{8}=1-\frac{5}{8}=\frac{8}{8}-\frac{5}{8}=\frac{3}{8}\\\\\frac{1}{8} \ \textless \  \frac{3}{8}\ therefore\ \frac{5}{8}\ is\ closest\ to\ \frac{1}{2}
4 0
3 years ago
Which pair of expressions below are equivalent?
Annette [7]

Answer: C, 7s + 3t and 3t + 7s.

Step-by-step explanation: Nothing is changing between the expressions except for their position. In addition, position does not matter though, so these two are the SAME EXPRESSION

3 0
3 years ago
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