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2 years ago

-3 = x + 12 It for math if somebody wants to help

Mathematics

2 answers:

Alekssandra [29.7K]2 years ago

6 0

$-3=x+12\\\\x+12=-3\\\\x=-3-12\\\\\huge\boxed{x=-15}$

lianna [129]2 years ago

4 0

Answer:

X= -15 is the correct answer

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Verify that -tan2x = (2tanx) / (sec^2x - 2)

sashaice [31]

Answer:

Below.

Step-by-step explanation:

- tan 2x = -2tanx / (1 - tan^2x)

Using the identity tan^2x = sec^2x - 1 and substituting for tan^2x:

- tan 2x = -2 tanx / (1 - (sec^2x - 1))

= 2 tanx / ( - 1(sec^2x + 2))

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3 years ago

What is 1/4 + 1/4 + 1/4 =

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2 years ago

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A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height

Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

$y(t)=43t-23t^{2}$

B) Instantaneous Velocity at t = 1

$y(1) = 43(1)-23(1)^2 = 20$

A) Formula:

Average velocity =

$\displaystyle\frac{\text{Displacement}}{\text{Time}}$

1) 0.01

$y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}$

2) 0.005 s

$y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}$

3) 0.002 s

$y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}$

4) 0.001 s

$y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}$