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svet-max [94.6K]
3 years ago
12

Luis has 8 petunias, 16 carnations, 20 pansies to plant flowerpots. If he plants that same number of each type of flower in flow

erpots, how many flowerpots will be use? How many of each type of flower will be in each flowerpot
Mathematics
1 answer:
Artemon [7]3 years ago
7 0

Answer:

  2 petunias, 4 carnations, 5 pansies

Step-by-step explanation:

  • 8 = 4×2
  • 16 = 4×4
  • 20 = 4×5

The greatest common divisor of the numbers of flowers is 4, so we expect the problem is saying Luis will prepare this many flower pots.

Then in each pot, Luis will have ...

  • 2 petunias
  • 4 carnations
  • 5 pansies

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Step-by-step explanation:

3/4 + 1/2 + 2 = 3_1/4

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16-3_1/4

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A 2-column table with 3 rows titled Units of Length. Column 1 is labeled Customary System Units with entries 1 inch, 1 foot, 1 m
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Step-by-step explanation:

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3 0
2 years ago
En un triangulo ABC, el angulo B mide 64° y el angulo C mide 72°. La bisectriz interior CD corta a la altura BH y a la bisectriz
nadezda [96]

Answer:

The difference between the greatest and the smallest angle of the triangle PBQ is 98°.

Step-by-step explanation:

The question is:

In a triangle ABC, angle B measures 64 ° and angle C measures 72°. The inner bisector CD intersects the height BH and the bisector BM at P and Q respectively. Find the difference between the greatest and the smallest angle of the triangle PBQ.

Solution:

Consider the triangle ABC.

The measure of angle A is:

angle A + angle B + angle C = 180°

angle A = 180° - angle B - angle C

             = 180° - 72° - 64°

             = 44°  

It is provided that CD and BM are bisectors.

That:

angle BCP = angle PCH = 36°

angle CBQ = angle QBD = 32°

angle BHC = 90°

Compute the measure of angle HBC as follows:

angle HBC = 180° - angle BHC + angle BCH

                  = 180° - 90° - 72°

                  = 18°

Compute the measure of angle BPC as follows:

angle BPC = 180° - angle PCB + angle CBP

                  = 180° - 18° - 36°

                  = 126°

Then the measure of angle BPQ will be:

angle BPQ = 180° - angle BPC

                  = 180° - 126°

angle BPQ = 54°

Compute the measure of angle PBQ as follows:

angle PBQ = angle B - angle QBD - angle HBC

                  = 64° - 32° - 18°

angle PBQ = 14°

Compute the measure of angle BQP as follows:

angle BQP = 180° - angle PBQ - angle BPQ

                  = 180° - 14° - 54°  

angle BQP = 112°

So, the greatest and the smallest angle of the triangle PBQ are:

angle BQP = 112°

angle PBQ = 14°

Compute the difference:

<em>d</em> = angle BQP - angle PBQ

  = 112° - 14°

  = 98°

Thus, the difference between the greatest and the smallest angle of the triangle PBQ is 98°.

4 0
3 years ago
????????????????????
Ilia_Sergeevich [38]

Answer:

your answer would be D....

3 0
3 years ago
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