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antiseptic1488 [7]
3 years ago
10

Diana ran a quarter mile straight down the street.becky ran a quarter mile on the track.who ran more?

Mathematics
1 answer:
Dovator [93]3 years ago
6 0
Neither they both ran a quarter mile
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Solution:

we have been asked to verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial 4x^3+20x^2+2x-3

To verify that whether the given values are zeros or not we will substitute the values in the given Polynomial, if it will returns zero, it mean that value is Zero of the polynomial. But if it return any thing other than zeros it mean that value is not the zero of the polynomial.

Let f(x)=4x^3+20x^2+2x-3\\\\\text{when x=-5}\\\\f(-5)=4(-5)^3+20(-5)^2+2(-5)-3=-13\\\\\text{when x=}\frac{1}{2}\\

f( \frac{1}{2} ) = 4 ( \frac{1}{2} )^3+20(\frac{1}{2})^2+2(\frac{1}{2})-3=\frac{7}{2}\\\\

\text{when x=}\frac{3}{4}\\\\

f( \frac{3}{4} ) = 4 ( \frac{3}{4} )^3+20(\frac{3}{4})^2+2(\frac{3}{4})-3=\frac{183}{16}\\

Hence -5, 1/2, and 3/4 are not the zeroes of the given Polynomial.

Since sum of roots=\frac{-b}{a}= \frac{-20}{4}=-5\\

But -5+\frac{1}{2}+\frac{3}{4}=  \frac{-15}{4}\neq-5

Hence we do not find any relation between the coefficients and zeros.

Anyway if the given values doesn't represents the zeros then those given values will not have any relation with the coefficients of the p[polynomial.

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3 years ago
−2(2x+3)≤26<br><br>-<br><br>2<br><br>2<br><br>x<br><br>+<br><br>3<br><br>≤<br><br>26<br><br>?
SashulF [63]

\huge \boxed{\mathbb{QUESTION} \downarrow}

- 2 ( 2 x + 3 ) \leq 26.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

- 2 ( 2 x + 3 ) \leq 26

Divide both sides by -2. We know that since 2 is negative, it'll be < (less than) 0. So, the direction of inequality will change.

2x+3\geq \frac{26}{-2}  \\

Divide 26 by -2..we'll get the answer as -13.

2x+3\geq -13

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Subtracting -13 by 3..we'll get the answer as -16.

2x\geq -16

Divide both sides by 2. We know that since 2 is positive, the direction of inequality will remain the same.

x\geq \frac{-16}{2}  \\

Divide -16 by 2..we'll get the answer as -8.

\huge \boxed{ \boxed{ \bf \: x\geq -8 }}

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