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MrRa [10]
4 years ago
10

What are the answers to problem one and to WILL GIVE BRAINLEST AND SHOW YOUR WORK

Mathematics
2 answers:
lutik1710 [3]4 years ago
7 0
The answer is: $19.56

4 * $4.89= $19.56
sweet [91]4 years ago
5 0
The answer is: $19.56

4 * $4.89= $19.56
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Taisha is making birthday gift bags. she wants to put 1/2 pound of chocolate in each bag. she has 4 3/4 pounds of chocolate. how
Varvara68 [4.7K]

Taisha is making gift bags for birthday. She intends to fill each bag with ½ pound of chocolate. Her chocolate bag weighs 4 ¾ pounds. Taisha can make 9.5 gift bags for the birthday.

This is calculated as,

There are 4 ¾  pounds of chocolate. 

Each bag will have ½  pound of chocolate. 

½ pound × Gift bags = 4 ¾ pounds.

4 ¾ pounds ÷ ½ pound = Gift bags.

4 ¾ pounds is 4.75 pounds and ½ pound is 0.5 pounds.

4.75 pounds ÷ 0.5 pound = 9.5 bags. 

Hence , Taisha could make 9.5 gift bags for the birthday.

To solve more such problems on Pounds visit : brainly.com/question/20550400

#SPJ4

7 0
2 years ago
One Step Equations <br> -104=8x<br><br> Please show your work, thank you.
In-s [12.5K]

Answer:

= − 1 3

Step-by-step explanation:

8x/8 = -104/8

Brainliest?

4 0
3 years ago
Consider the geometric series S(x)=1+2(x−3)+4(x−3)^2+8(x−3)^3+⋯
sergij07 [2.7K]
Consider the geometric series S(x)=1+2(x−3)+4(x−3)^2+8(x−3)^3+⋯
Giving your answer as an interval, find all values of x for which the series converges.
Now assuming that x is in your interval above, find a simple formula for S(x).
5 0
3 years ago
Read 2 more answers
Train “A” leaves Westtown and travels at 50 mph toward Smithville, 330 miles away. At the same time, Train “B” leaves Smithville
lesya692 [45]

train A travels at 50 mph

train B travels at 60 mph

60 +50 = 110

330/110 = 3

they will meet in 3 hours


3 0
3 years ago
A university with a high water bill is interested in estimating the mean amount of time that students spend in the shower each d
Bas_tet [7]

Answer: (4.0845,\ 6.5755)

Step-by-step explanation:

As per given , we have

n = 11

\overline{x}=5.33\\\\ s=1.33

Since population standard deviation is missing, so we use t-test.

Critical t-value for 99% confidence :

t_{\alpha/2,\ n-1}=3.106   [using two-tailed t-value table]

Confidence interval :

\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}}\\\\= 5.33\pm (3.1060)\dfrac{1.33}{\sqrt{11}}\\\\\approx5.33\pm1.2455\\\\=(5.33-1.2455,\ 5.33+1.2455)\\\\=(4.0845,\ 6.5755)

Hence,  99% confidence interval for the mean amount of time that students spend in the shower each day.= (4.0845,\ 6.5755)

7 0
3 years ago
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