Question

Consider the geometric series S(x)=1+2(x−3)+4(x−3)^2+8(x−3)^3+⋯

Answer 1

Answer:

Consider the geometric series S(x)=1+2(x−3)+4(x−3)^2+8(x−3)^3+⋯

Giving your answer as an interval, find all values of x for which the series converges.

Now assuming that x is in your interval above, find a simple formula for S(x).

Step-by-step explanation:

Answer 2

Consider the geometric series S(x)=1+2(x−3)+4(x−3)^2+8(x−3)^3+⋯
Giving your answer as an interval, find all values of x for which the series converges.
Now assuming that x is in your interval above, find a simple formula for S(x).