Consider the geometric series S(x)=1+2(x−3)+4(x−3)^2+8(x−3)^3+⋯

Mathematics

2 answers:

aksik [14]3 years ago

7 0

Answer:

Consider the geometric series S(x)=1+2(x−3)+4(x−3)^2+8(x−3)^3+⋯

Giving your answer as an interval, find all values of x for which the series converges.

Now assuming that x is in your interval above, find a simple formula for S(x).

Step-by-step explanation:

sergij07 [2.7K]3 years ago

5 0

Consider the geometric series S(x)=1+2(x−3)+4(x−3)^2+8(x−3)^3+⋯
Giving your answer as an interval, find all values of x for which the series converges.
Now assuming that x is in your interval above, find a simple formula for S(x).

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