Given:
Two endpoints of a diameter of a circle:
P (-7, -10)
Q (3, 2)
a) To find the center of the circle, find the midpoint of the two points:
midpoint:
(x2 - x1 )/ 2 , (y2 - y1) / 2
x= (2 - (-7))/2 = 4.5
y= (3 - (-10))/2 = 6.5
Therefore, the center of the circle is at C(4.5, 6.5)
b) To find the radius of the circle, we need to find the distance between the two points and divide by 2.
d = √(y2-y1)^2 + (x2 - x1)^2
d = √(2-(-7))^2 + (3 - (-10))^2
d = 5√10 = diameter
r = d/2 = 5√10 /2
Answer:
See explanation
Step-by-step explanation:
look photo
Answer:
{- 11, - 1 }
Step-by-step explanation:
Since the coefficient of the x² term is 1 , to complete the square
add (half the coefficient of the x-term )² to both sides
x² + 2(6)x + 36 = - 11 + 36 ← complete the square on the left side
(x + 6)² = 25 ( take the square root of both sides
= ± 
x + 6 = ± 5 ( subtract 6 from both sides )
x = - 6 ± 5
x = - 6 + 5 = - 1 or x = - 6 - 5 = - 11
Answer: (-19/80, -1/2)
Step By Step Explanation:
First you want to do 2/5 - 7/8. Once you get -19/40, you want to divide it by 2. After doing this step, you will get -19/80. Next, you want to do the same thing with the other one. -2/5 -3/5 or 2/5+3/5 except the answer will be negative. Now you get -1/2. Therefore, the answer is (-19/80, -1/2). Sorry if my explanation is trashy.
