Angle A is the smallest.
It's truly simple; The triangle's smallest side is 10 units (used for unknown units of measurements). Angles A and E are both acute angles, however, angle E is larger due to side AD being larger than side ED. So, the angle has to widen in order to reach the full length.
4x = -36 Subtract 10 from both sides
x = -9 Divide by 4 on both sides
The function is:
B ( t ) = 4 * e^(0.8 t)
4 * e^(0.8 t) = 400
e^(0.8 t) = 400: 4
e^(0.8 t) = 100 / ln
ln e^(0.8 t) = ln 100 ( and since: ln e = 1 and ln e^x = x * ln e )
0.8 t = 4.6
t = 4.6 : 0.8 = 5.76 ≈ 6
Answer:
D ) 6 hours.
The sum of the angles of a quadrilateral is 360 degrees. So P+Q+R is 206, 360 - 206 = 154 degrees, the measure of angle S.
The four triangles, AQB, BRC, CSD, and DPA are all isosceles. So angle QBA = angle BAQ, etc. We find QBA = (180-24)/2 or 78 degrees.
RBC = (180-114)/2 = 33 degrees.
180 - (78 + 33) is the measure of angle B: 69 degrees.
The student should be able to see how to calculate the missing information from this.
500 seconds is greater. Since there are 60 seconds in one minute you would multiply 60 and 8.
60x8= 480
