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melomori [17]
3 years ago
8

The table shows the busiest airports, shipping ports, and rapid rail systems in the United States. Suppose you are doing a repor

t in which you have to research one entry from each column. You have no preference for any choices over any other choices. What is the probability that you would select Chicago O’Hare Intl. Airport, the port of Houston, Texas, and the Boston MBTA?
Mathematics
1 answer:
yaroslaw [1]3 years ago
6 0

Answer:

Texas,

Step-by-step explanation:

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A 14.5-gallon gasoline tank is full. How many gallons will it take to fill the tank? Write your answer as a mixed number.
Elena L [17]

Answer:

it will take 3 5/8 of gas to fill the tank

Step-by-step explanation:

14 1/2 - 10 7/8 can be re-written using improper fractions

29/2 - 87/8 We need a common denominator, which is 8

116/8 - 87/8 = 29/8 = 3 5/8 gal

7 0
2 years ago
Find the 2th term of the expansion of (a-b)^4.​
vladimir1956 [14]

The second term of the expansion is -4a^3b.

Solution:

Given expression:

(a-b)^4

To find the second term of the expansion.

(a-b)^4

Using Binomial theorem,

(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}

Here, a = a and b = –b

$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}

Substitute i = 0, we get

$\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}=1 \cdot \frac{4 !}{0 !(4-0) !} a^{4}=a^4

Substitute i = 1, we get

$\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}=\frac{4 !}{3!} a^{3}(-b)=-4 a^{3} b

Substitute i = 2, we get

$\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}=\frac{12}{2 !} a^{2}(-b)^{2}=6 a^{2} b^{2}

Substitute i = 3, we get

$\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}=\frac{4}{1 !} a(-b)^{3}=-4 a b^{3}

Substitute i = 4, we get

$\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=1 \cdot \frac{(-b)^{4}}{(4-4) !}=b^{4}

Therefore,

$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}

=\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}+\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}+\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}+\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}+\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=a^{4}-4 a^{3} b+6 a^{2} b^{2}-4 a b^{3}+b^{4}

Hence the second term of the expansion is -4a^3b.

3 0
3 years ago
please answer correctly! This has 2 slides of questions but please answer correctly. I need this <3 :)
Darina [25.2K]

Answer:

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Can anyone me with this math question?
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This is geometry.. If lines l and M are parallel than we look at the line that goes from bottom left to the top right. this is called the transversal. When lines are parallel then alternate interior angles are congruent. That means opposite sides of the transversal and inside the parallel lines. That means 28 and  are congruent.

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3 years ago
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