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melomori [17]
3 years ago
8

The table shows the busiest airports, shipping ports, and rapid rail systems in the United States. Suppose you are doing a repor

t in which you have to research one entry from each column. You have no preference for any choices over any other choices. What is the probability that you would select Chicago O’Hare Intl. Airport, the port of Houston, Texas, and the Boston MBTA?
Mathematics
1 answer:
yaroslaw [1]3 years ago
6 0

Answer:

Texas,

Step-by-step explanation:

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The comma after "however" should be removed
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No it shouldent

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Because it needs a comma

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301 345 305 394 328 317 361 325 310 362 What values of minimum, Q1, median, Q3, and maximum should be used to make a box plot fo
Hunter-Best [27]
First, put the numbers in order...very important
301,305,310,317,325,328,345,361,362,394

minimum (smallest number) = 301
Q1 = 310
Q2 (middle number) = (325 + 328)/2 = 653/2 = 326.5
Q3 = 361
maximum (largest number) = 394

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3 years ago
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Wewaii [24]

Answer: answer is c

Step-by-step explanation: quizlet

4 0
3 years ago
Assume the random variable X is normally distributed with mean 53 and standard deviation of 6. Find the 9th percentile
satela [25.4K]

Answer:

<em>The 9th percentile of X is 44.96</em>

Step-by-step explanation:

<u>Percentiles for a Normal Distribution</u>

The standard normal distribution can be used for computing percentiles. For example, the median is the 50th percentile being the center value, the first quartile is the 25th percentile, and so on.

To compute percentiles of a normal distribution we can use the formula

X=\mu+z\sigma

Where \mu is the mean, \sigma is the standard deviation of the variable X, and z is the z-score value from the standard tables

The value of X can also be directly obtained from digital tables included in math packages and tools like Excel.

The Excel NORM.INV Function calculates the inverse of the cumulative Normal Distribution Function for a given value of p, \mu and \sigma.

We'll use the values

p=9\%=0.09,\ \mu=53, \ \sigma=6

NORM.INV(0.09,53,6) results in 44.96 which means the 9th percentile of X is 44.96

We could have used the standard normal distribution, which only needs the value of p

NORM.S.INV( 0.09 )=-1.34

That is the value of z, we now apply the formula

X=\mu+z\sigma

X=53+(-1.34)\cdot 6=44.96

We get the very same result as before

6 0
3 years ago
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