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Pepsi [2]
3 years ago
6

Ann has an empty cup and add 1 ounce of water per second. Bob has 12 ounces of water and drinks 2 ounces per second. After how m

any seconds will they have the same amount of water
Mathematics
1 answer:
Lyrx [107]3 years ago
4 0

Answer:

4 seconds

Step-by-step explanation:

Given

Ann has an empty cup and add 1 ounce of water per second

let the number of seconds required to fill the cup be x

let the total be y

in x seconds Ann will have x ounces of water in the cup.

so the total amount of water in Ann's cup will be

y=x-----------1

Bob has 12 ounces of water and drinks 2 ounces per second

also, let the number of seconds required to empty the cup be x

let the total be y

y= 12-2x--------------2

Step two:

equate the two equations above and solve for x

x=12-2x

collect like terms

x+2x=12\\\\3x=12

divide both sides by 3

x=12/3\\\\x= 4 seconds

Therefore, after about 4 seconds Ann and Bob's cup will have the same amount of water

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Find the coefficient of variation for each of the two sets of data, then compare the variation. Round results to one decimal pla
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Here is  the correct computation of the question given.

Find the coefficient of variation for each of the two sets of data, then compare the variation. Round results to one decimal place. Listed below are the systolic blood pressures (in mm Hg) for a sample of men aged 20-29 and for a sample of men aged 60-69.

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a)

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b)

Men aged 20-29: 4.4%

Men aged 60-69: 8.3%

There is substantially more variation in blood pressures of the men aged 60-69.

c)

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Men aged 60-69: 10.2 %

There is substantially more variation in blood pressures of the men aged 60-69.

d)

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Men aged 60-69: 4.7%

There is more variation in blood pressures of the men aged 20-29.

Answer:

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Men aged 20-29: 4.6%

Men aged 60-69: 10.2 %

There is substantially more variation in blood pressures of the men aged 60-69.

Step-by-step explanation:

From the given question:

The coefficient of variation can be determined by the relation:

coefficient \ of  \ variation = \dfrac{standard \ deviation}{mean}*100

We will need to determine the coefficient of variation both men age 20 - 29 and men age 60 -69

To start with;

The coefficient of men age 20 -29

Let's first find the mean and standard deviation before we can do that ;

SO .

Mean = \dfrac{\sum \limits^{n}_{i-1}x_i}{n}

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Standard deviation  = \sqrt{\dfrac{\sum (x_i- \bar x)^2}{(n-1)} }

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The coefficient \ of  \ variation = \dfrac{standard \ deviation}{mean}*100

coefficient \ of  \ variation = \dfrac{5.68}{123.33}*100

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Mean = \dfrac{\sum \limits^{n}_{i-1}x_i}{n}

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Standard deviation  = \sqrt{\dfrac{\sum (x_i- \bar x)^2}{(n-1)} }

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coefficient \ of  \ variation = \dfrac{14.48}{142}*100

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Thus; Option C is correct.

Men aged 20-29: 4.6%

Men aged 60-69: 10.2 %

There is substantially more variation in blood pressures of the men aged 60-69.

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