This is the concept of trajectories;
We are required to calculate the time taken for the base ball whose distant to reach the maximum height has been modeled by h=-16t^2+64t+4.2 took to hit the ground. Here we proceed as follows;
At the time when the base ball hits the ground the height,h=0
Thus;
-16t^2+64t+4.2=0
this is a quadratic equation, to solve the quadratic equation we use the formula;
t=[-b+/- sqrt(b^2-4ac)]/(2a)
where;
a=-16,b=64, c=4.2
thus substituting the values in our formula we get:
t=[-64+/-sqrt(64^2-4*(-16)*4.2)]/(-16*2)
t=[-64+/- sqrt(4364.8)]/(-32)
t=[-64+/-66.1]/(-32)
t=4.1 or-0.1
thus the we take the positive value t=4.1 and we conclude that the time taken for the ball to hit the ground was 4.1 seconds
Step-by-step explanation:
<h3>stay safe healthy and happy...</h3>
Step-by-step explanation:
denominators showing all working <3
Hey there!!
What is slope-intercept form :
... y = mx + b
( a ) Given :
... ( 2 , -2 ) and slope=1.4
... y = mx + b
... -2 = 2×1.4 + b
... -2 = 2.8 + b
... -4.8 = b
The slope-intercept form :
... y = 1.4x - 4.8
( b ) Given :
... ( -1 , 4 ) and slope = -3.
y = mx + b
... 4 = -3×-1 + b
... 4 = 3 + b
... 1 = b
The slope-intercept form :
... y = -3x + 1
Note :
( m = slope and b = y-intercept )
Hope my answer helps!!