Hey there! :D
First, find the slope.
m= (y2-y1)/(x2-x1) I'm using points (0,3) and (1,5)
m=(5-3)/(1-0)
m= 2/1
m=2
Now, plug that into point slope. Use point (1,5) m=2
y-y1= m(x-x1)
y-5= 2(x-1)
Distribute.
y-5=2x-2
Add 5 to both sides.
y=2x+3 == equation of the line in slope intercept form. y=mx+b
I hope this helps!
~kaikers
Answer:
2x+15
Step-by-step explanation:
because this is easy
Use x+2y=8
Subtract 2y to make
x=8-2y
Plug this in to the other equation
3(8-2y)+2y=6
Distribute the 3
24-6y+2y=6
Combine like terms
24-4y=6
Solve
18/4=y, 9/2=y
Plug and solve for x
X+2y=8
X+(2*9/2)=8
X+9=8
X=-1
Answer:
(I) (-5) is a zero of P(x)
(II) 5 is a zero of P(x)
(III) (-5/2) is a zero of P(x)
Step-by-step explanation:
<h3>
(I) P(x) = x + 5</h3>
Here, P(x) = x + 5
To find the zeroes of P(x)
let P(x) = 0
∴ x + 5 = 0
∴ x = (-5)
Thus, (-5) is a zero of P(x)
<h3>(II) P(x) = x - 5</h3>
Here, P(x) = x - 5
To find the zeroes of P(x)
let P(x) = 0
∴ x - 5 = 0
∴ x = 5
Thus, 5 is a zero of P(x)
<h3>(III) P(x) = 2x + 5</h3>
Here, P(x) = 2x + 5
To find the zeroes of P(x)
let P(x) = 0
∴ 2x + 5 = 0
∴ 2x = -5
∴ x = (-5/2)
Thus, (-5/2) is a zero of P(x)
<u>-</u><u>TheUnknownScientist</u>
Step-by-step explanation:
The slope-intercept form of an equation of a line:

- slope
- y-intercept

19) and 20) you have in other your question.