Math help again please

Mathematics

1 answer:

vovangra [49]3 years ago

8 0

Hey there! :D

First, find the slope.

m= (y2-y1)/(x2-x1) I'm using points (0,3) and (1,5)

m=(5-3)/(1-0)
m= 2/1
m=2

Now, plug that into point slope. Use point (1,5) m=2

y-y1= m(x-x1)

y-5= 2(x-1)

Distribute.

y-5=2x-2

Add 5 to both sides.

y=2x+3 == equation of the line in slope intercept form. y=mx+b

I hope this helps!
~kaikers

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ABCD is a rectangle. The length of BD is 8 units, and m angle ABD is 67°. The length of AC is units, and m angle CDB is °.

Marina86 [1]

See the attached picture to better understand the problem
we know that
in rectangle ABCD
AB=CD
and
AD=BC
therefore
the triangle ACD and triangle ABC are congruent
so
BD=AC
BD=8 units

the answer part a) is
BD= 8 units

Part b) Find angle CBD

we know that
∠ABD+∠CBD=90°---------> by complementary angles
so
∠CBD=90-∠ABD-----> 90-67----> 23°
∠CBD=23°

the answer Part b) is
∠CBD=23 degrees