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marta [7]
2 years ago
13

What is the true solution to 3 in 2 + in 8 = 2 in (4x)

Mathematics
2 answers:
11Alexandr11 [23.1K]2 years ago
5 0
The first step for solving this equation is to determine the defined range.
3㏑(2) + ㏑(8) = 2㏑(4x), x > 0
Write the number 8 in exponential form.
3㏑(2) + ㏑(2³) = 2㏑(4x)
Using ㏑(a^{x}) = x × ㏑(a),, transform the expression.
3㏑(2) + 3㏑(2) = 2㏑(4x)
Now collect the like terms on the left side of the equation.
6㏑(2) = 2㏑(4x)
Switch the sides of the equation.
2㏑(4x) = 6㏑(2)
Using x × ㏑(a) = ㏑(a^{x}),, transform the expression on the left side of the equation.
㏑((4x)²) = 6㏑(2)
Using x × ㏑(a) = ㏑(a^{x}),, transform the expression on the right side of the equation.
㏑((4x)²) = ㏑(2^{6})
Since the bases of the logarithms are the same,, you need to set the arguments equal.
(4x)² = 2^{6}
Take the square root of both sides of the equation and remember to use both the positive and negative roots.
4x = +/- 8
Now separate the equation into 2 possible cases.
4x = 8
4x = -8
Solve the top equation for x.
x = 2
Solve the bottom equation for x.
x = 2
         , x > 0
x = -2
Lastly,, check if the solution is in the defined range to find your final answer.
x = 2
This means that the correct answer to your question is x = 2.
Let me know if you have any further questions
:)
EleoNora [17]2 years ago
5 0

Answer:

b

Step-by-step explanation:

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4 0
3 years ago
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lianna [129]
Multiplying complex numbers is a lot like multiplying binomial terms. The only relation one has to remember when dealing with complex numbers is that i² = -1.

Now let us try to multiply binomials. This is done by adding the products of the first term of the first binomial distributed to the second binomial, and the second term of the first binomial distributed to the second binomial. This is done below:

(<span>3 – 5i)(–2 + 4i)  = -6 + 12i + 10i -20i²
</span>
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Among the choices, the correct answer is B.
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Read 2 more answers
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