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Allushta [10]
3 years ago
7

1. Write an algebra equation for each purchase. I (Mickey) bought an ice cream treat and a bottle of water for $10. Pam purchase

d an ice cream treat and two bottles of water for $14. Use your equations and reasoning skills to find the price of a bottle of water and an ice cream treat.
Mathematics
1 answer:
Ne4ueva [31]3 years ago
5 0

x+y=10

x+2y=14
x is common in both so u have to subtract the second one from 1st
x-x + y-2y = 10-14
-y = -4
y=4
which means bottle of water (y) = 4
and then substitute 4 in equation (x+y=10 or x+2y=10)
x + 4 = 10
x=6
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Solve the problem.
zmey [24]

Answer:

the percent of increase is 24%

Step-by-step explanation:

The percent of increase in general could be calculate as:

\frac{Vf - Vi}{Vi} *100

where Vf is final value and Vi is initial value.

From the question we know that Vi is equal to 25 and Vf is equal to 31. Replacing this values on the equation we get:

\frac{31-25}{25} *100=24%

That's mean that at second attempt the percent of increase is 24%, taking into account that at the first attempt a student get 25 questions correct.

6 0
3 years ago
In a multiple choice quiz there are 5 questions and 4 choices for each question (a, b, c, d). Robin has not studied for the quiz
Ahat [919]

Answer:

a) There is a 18.75% probability that the first question that she gets right is the second question.

b) There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

c) There is a 10.35% probability that she gets the majority of the questions right.

Step-by-step explanation:

Each question can have two outcomes. Either it is right, or it is wrong. So, for b) and c), we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem we have that:

Each question has 4 choices. So for each question, Robin has a \frac{1}{4} = 0.25 probability of getting ir right. So \pi = 0.25. There are five questions, so n = 5.

(a) What is the probability that the first question she gets right is the second question?

There is a 75% probability of getting the first question wrong and there is a 25% probability of getting the second question right. These probabilities are independent.

So

P = 0.75(0.25) = 0.1875

There is a 18.75% probability that the first question that she gets right is the second question.

(b) What is the probability that she gets exactly 1 or exactly 2 questions right?

This is: P = P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 1) = C_{5,1}.(0.25)^{1}.(0.75)^{4} = 0.3955

P(X = 2) = C_{5,2}.(0.25)^{2}.(0.75)^{3} = 0.2637

P = P(X = 1) + P(X = 2) = 0.3955 + 0.2637 = 0.6592

There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

(c) What is the probability that she gets the majority of the questions right?

That is the probability that she gets 3, 4 or 5 questions right.

P = P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 3) = C_{5,3}.(0.25)^{3}.(0.75)^{2} = 0.0879

P(X = 4) = C_{5,4}.(0.25)^{4}.(0.75)^{1} = 0.0146

P(X = 5) = C_{5,5}.(0.25)^{5}.(0.75)^{0} = 0.001

P = P(X = 3) + P(X = 4) + P(X = 5) = 0.0879 + 0.0146 + 0.001 = 0.1035

There is a 10.35% probability that she gets the majority of the questions right.

6 0
3 years ago
Please help me!!! 30 points, will report for ridiculous responses.
Bumek [7]

Answer:

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a:

x = 64 + 45 = \boxed{109}

b:

3x + 6 = 153 so

3x = 147 so

x = \boxed\boxed{49}

3 0
3 years ago
Is this right yes or no
tatyana61 [14]

Answer:

yes you did that correctly

6 0
2 years ago
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kaheart [24]

Answer:

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Step-by-step explanation:

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