<h2>
The area of a triangle is =54 square units</h2><h2>
The perpendicular distance from B to AC is = 
</h2>
Step-by-step explanation:
Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)
The area of a triangle is= ![\frac{1}{2} [x_1(y_2-y_3) +x_2 (y_3- y_1)+x_3(y_1-y_2)]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Bx_1%28y_2-y_3%29%20%2Bx_2%20%28y_3-%20y_1%29%2Bx_3%28y_1-y_2%29%5D)
=![|\frac{1}{2} [2(2-8+12(8-1)+12(1-2)]|](https://tex.z-dn.net/?f=%7C%5Cfrac%7B1%7D%7B2%7D%20%5B2%282-8%2B12%288-1%29%2B12%281-2%29%5D%7C)
=
= 54 square units
The length of AC = 
= 
=
units
Let the perpendicular distance from B to AC be = x
According To Problem
⇔
units
Therefore the perpendicular distance from B to AC is =
B) p=9t
he gets paid $9/hr, and his pay depends how many hours he works.
Answer:
(
h
∘
f
∘
g
)
(
x
)
is known as a composite function. Here's how composite functions work:
let's say that
x
=
1
. Your function
g
(
x
)
=
1
3
(
x
)
now produces a
y
output of
1
3
, since
g
(
1
)
=
1
3
(
1
)
. Within a composite function, the y-value of one function becomes the x-value of the next, like so:
g
(
1
)
=
1
3
⇒
f
(
1
3
)
=
17
3
⇒
h
(
17
3
)
=
17
Therefore,
(
h
∘
f
∘
g
)
(
1
)
=
17
Based on this, to find the function for
(
h
∘
f
∘
g
)
(
x
)
(combined from right to left, by the way), simply replace
x
in
f
(
x
)
with the function
g
(
x
)
, and replace
x
in
h
(
x
)
with the function of
(
f
∘
g
)
(
x
)
, to get
(
h
∘
f
∘
g
)
(
x
)
.
This, simplified, is equal to
2
x
+
15
, and therefore
(
h
∘
f
∘
g
)
(
1
)
=
2
(
1
)
+
15
=
17
Hope that helps!
Converting 25 degrees to radians:
180° = π radians.
1° = π/180 radians.
25° = (π/180 radians) * 25
= (25/180) * π radians.
Leaving the answer in terms of π, 25/180 = 5/36
= (25/180) * π radians = (5/36)π radians or ≈ 0.1389π radians.
Therefore 25° = (5/36)π radians or ≈ 0.1389π radians
I hope this explains it.
I think why you did not get it was because you did not leave your answer in terms of π or as a multiple of π, so as a multiple of π our answer is:
= (5/36)π radians or ≈ 0.1389π radians
