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2 years ago

What is the absolute of -32

Mathematics

2 answers:

luda_lava [24]2 years ago

8 0

The answer is 32 because on a number line it is the distance between the number and zero.

Ganezh [65]2 years ago

6 0

Any absolute negative number will come back as the same number itself but positive !:)

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Solve with elimination.

wlad13 [49]

Answer:y=6.61,x=-6.46

Step-by-step explanation:

3x+7y=-26(×5)

5x+3y=-14(×3)

=15x+35y=-130

15x+9y=-42

subtracting the 2 equations =15x-15x+35y-9y=-130-(-42)

=26y=172

y=172÷26

y=6.61

substitute y in the first equation=3x+6.61=-26

3x=-26+6.61=-19.39

x=-19.39÷3

x=-6.46

7 0

2 years ago

alex walked 1 mile in 15 minutes. Sally walked 3520 yards in 24 minutes . in miles per hour , how much faster did sally walk tha

Leni [432]

Answer: Sally walked 3 minutes faster per mile

Hope it helped!

7 0

2 years ago

(09.06 HC) The function H(t) = −16t2 + 112t + 24 shows the height H(t), in feet, of a cannon ball after t seconds. A second cann

erma4kov [3.2K]

PART A:

The table of h(t) and g(t) for the value of x between 4 and 7 inclusive are shown below.

The solution for h(x)=g(x) lies between x = 4 and x = 5, this is becuase the range of value given by h(4) and h(5) and g(4) and g(5).

The graph is shown in picture 2 to confirm this. The two functions intersect each other between x = 4 and x = 5

PART B:

The point of intersection is the point where the cannon balls will collide.

3 0

3 years ago

Read 2 more answers

Ppppppppppllllllllls I need helppppppp

Phantasy [73]

Answer:

ΔABC≅ΔDEC by AAS

Step-by-step explanation:

You can use the AAS method of congruency.

Since you already have <BAC and <EDC congruent to eachother, and sides BC and EC congruent to each other, you only need that one remaining angle in between. <ACB can be proven congruent to <DCE by the Vertical Angles Theorem, and that gives you the AAS you need to prove that these two triangles are congruent

Hope this helped.

5 0

2 years ago

Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?

Bogdan [553]

Step-by-step explanation:

$\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}$

$\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}$

$\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}$

$\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}$

Taking sin²θ common in both numerator & denominator, We get :

$\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}$