x+2 > 10 solves to x > 8 after we subtract 2 from both sides
So set A is the set of real numbers that are larger than 8. The value 8 itself is not in set A. The same can be said about 5 as well.
Set B is the set of values that are larger than 5 since 2x > 10 turns into x > 5 after dividing both sides by 2. The value x = 5 is not in set B since x > 5 would turn into 5 > 5 which is false. The values x = 6, x = 8, and x = 9 are in set B.
----------------
Summarizing everything, we can say...
5 is not in set A. True
5 is in set B. False
6 is in set A. False
6 is not in set B. False
8 is not in set A. True
8 is in set B. True
9 is in set A. True
9 is not in set B. False
EXPLANATION
Let's see the facts:
$Sandwiches= 3*$Salads
Bill = $24.92
We can represent this in an equation:
Total Bill = Sandwiches + Salads
Let's call to Sandwiches "x" to Salads "y" and to Bill "B"
Then, the equation will be:
B = x+y = (3*y) + y
Applying distributive property:
24.92 = 3y + y
Adding similar terms:
24.92 = 4y
Dividing both sides by 4:
6.23 = y
Switching:
y=6.23
As we know, y variable represent the salads cost, so:
Answer is $6.23.
Hey there!☺
Equation
−4(10 − a) = 36 Simplify both sides
(−4)(10) + (−4)(−a) = 36 Distribute
−40 + 4a = 36
4a − 40 = 36
4a - 40 + 40 = 36 + 40 Add 40 to both sides
4a = 76
4a/4 = 76/4 Divide both sides by 4
76/4 = 19 Simplify 76/4
a = 19
Hope this helps!
P E M D A S
Pren
Equ
Multiply
Divide
Add
Subtract
