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tino4ka555 [31]
3 years ago
11

Please answerrrrrrrrrrr

Mathematics
1 answer:
saul85 [17]3 years ago
7 0

Answer:

a c e

Step-by-step explanation:

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Hey guys so I forgot what an exponent is.<br><br>This is what I put:​
WINSTONCH [101]

Step-by-step explanation:

An exponent is that number multiplied by itself however many times it say

Exp: 10³=10×10×10

6 0
2 years ago
@mehek14
gayaneshka [121]
X=cost per hamburgurs
y=cost per hot dog

200x+150y=1450
200x+250y=1750

we can multiply first equation by -1 and add to 2nd

-200x-150y=-1450
<u>200x+250y=1750 +</u>
0x+100y=300

100y=300
divide both sides by 100
y=3

sub back

200x+150y=1450
200x+150(3)=1450
200x+450=1450
minus 450 both sides
200x=1000
divide both sides by 200
x=5


the cost of a hamburgur is $5
the cost of a hot dog is $3
8 0
3 years ago
Read 2 more answers
Please answer these 4 math questions for me! Pretty easy! need then ASAP!!!!! I have to get them right or my life is doomed! (ca
Grace [21]

Answer:

Last one is 90 and -65, 3rd one is 120 feet i think, and i am 99% sure 2nd one is 129

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
ASAP someone please simply two exponents
zhannawk [14.2K]

Answer:

1.) m^{15}

2.) =\frac{1}{y^{15}}

Give me a comment if you want the explanation.

1.) \mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0

\left(m^3\right)^5=m^{3\cdot \:5}

\mathrm{Multiply\:the\:numbers:}\:3\cdot \:5=15

=m^{15}

2.) \mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0

\left(y^{-3}\right)^5=y^{-3\cdot \:5}

=y^{-3\cdot \:5}

=y^{-15}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

=\frac{1}{y^{15}}

4 0
3 years ago
The dimensions of a rectangles are 8cm and 12cm. What is the ratio of its length to its perimeter?
kari74 [83]

Answer:

Dimensions = 8 CM and 12 CM

length = 12 CM

width = 8 cm

perimeter = 2 ( length + width)

= 2( 12 + 8)

= 2 ( 20)

= 40 CM

ratio = 12/40

= 6/20

= 3/10

<h2>= 3 : 10 </h2>
3 0
2 years ago
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