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4 years ago

WHAT IS 4 TIMES TWO THIRDS IN A MIXED FRACTION

2 answers:

7 0

\frac{4}{1} × \frac{2}{3} = \frac{8}{3} You then divide the numerator(top) by the denominator(bottom) \frac{8}{3} =2 \frac{2}{3} Your answer is 2 \frac{2}{3}

Alex73 [517]4 years ago

3 0

$\frac{4}{1}$ × $\frac{2}{3}$ = $\frac{8}{3}$
You then divide the numerator(top) by the denominator(bottom)
$\frac{8}{3}$ = $2 \frac{2}{3}$
Your answer is $2 \frac{2}{3}$

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-34.78/-3.7 need help please help ASAP

nataly862011 [7]

Answer:

9.4

Step-by-step explanation:

4 0

3 years ago

What is the value of x in the diagram?

Verizon [17]

2 lines parallel, and 2 triangles have a common angle
So the smaller Δ is similar to the bigger Δ (AA Similarity)
9:(4x-2)+9=12:(3x+2)+12
9:4x+7=12:3x+14
9(3x+14)=12(4x+7)
27x+126=48x+84
21x=42
x=2
So the answer is x=2

5 0

4 years ago

Legalize Marijuana, Part II. As discussed in Exercise 6.12, the 2010 General Social Survey reported a sample where about 48% of

kvv77 [185]

Answer:

Around 2397 Americans must be surveyed to get a margin of error of 2%.

Step-by-step explanation:

We are given the following in the question:

Proportion of US residents who thinks marijuana should be made legal = 48%

$\hat{p} = 0.48$

We have to construct a 95% confidence interval.

Margin of error = 2% = 0.02

Formula for margin of error =

$z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

Putting values, we get,

$0.02 = 1.96\times \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\0.02 = 1.96\times \sqrt{\dfrac{0.48(1-0.48)}{n}}\\\\\sqrt{n} = 1.96\times \dfrac{\sqrt{0.48(1-0.48)}}{0.02}\\\\\sqrt{n}=48.96\\n = 2397.0816\approx 2397$

Thus, around 2397 Americans must be surveyed to get a margin of error of 2%.

8 0

3 years ago

Which number round to 4,100 when rounded to the nearest hundred

scoray [572]

The answer would be B.

4 0

3 years ago

How do i check an equation for extraneous solutions?

Marina86 [1]

Example:

$\sqrt x(x+1)=0$

This suggests two solutions, $x=0$ and $x=-1$ .

However, upon plugging these solutions back into the equation, you get

$\sqrt0(0+1)=0(1)=0$

which checks out, but

$\sqrt{-1}(1-1)=0$

does not because $\sqrt x$ is defined only for $x\ge0$ (assuming you're looking for real solutions only). So, we call $x=-1$ an extraneous solution, and the complete solution set (over the real numbers) is $x=0$ .

7 0

3 years ago

Read 2 more answers