Tgα = tan(α) = sqrt(2)/1 = opposite/ adjacent
opposite = sqrt(2)
adjacent = 1
hypotenuse = sqrt(opposite^2 + adjacent^2)
= sqrt(sqrt(2)^2 + 1^2) = sqrt(3)
sin(α) = opposite/hypotenuse
= sqrt(2)/sqrt(3)
cos(α) = adjacent/hypotenuse
= 1/sqrt(3)
now we can calculate the value of
5sin²α+3cos²α / 3sin²α-5cos²α
... do the math
Answer:
Step-by-step explanation:
q is TFTF
~q use negation, not q so is the opposite of q : FTFT
p↔~q use biconditional ,and will be True only is both statements are T or both are F
p values are TTFF ↔~q values are FTFT : FTTF
(p↔~q )∧~q use conjunction, that is True only if both statements are T
(p↔~q ) values are FTTF ∧~q values are FTFT : FTFF
(p↔~q )∧~q → p use a conditional statement, where only True False will give a F
(p↔~q )∧~q values are FTFF → p values are TTFF : TTTT
You can look at -32 as being -2^5 so if you write (-2^5)^3/5 the 5's cancel out making it -2^3 which equals -8
Answer:
Divide StartFraction a Over 11 EndFraction by 11; the solution is 540.
Step-by-step explanation:
Answer:
3/2 x-5
Step-by-step explanation: