An Ocean Thermal Energy Conversion (OTEC) power plant built in Hawaii in 1987 was designed to operate between the temperature li
mits of 86°F at the ocean surface and 41°F at a depth of 2100 ft. About 13,300 gpm of cold seawater was to be pumped from deep ocean through a 40-in-diameter pipe to serve as the cooling medium or heat sink. If the cooling water experiences a temperature rise of 6°F and the thermal efficiency is 2.5 percent, determine the amount of power generated. Take the density of seawater to be 64 lbm/ft3. Also, take the specific heat of water to be c = 1.0 Btu/lbm·°F.
2 answers:
Answer:
power generated = 307.84 Kw
Explanation:
The Given data
Tk = 86 f = 303.15k
To = 41 f = 278.15k
thermal efficiency ( n ) = 0.025
Q = 13300 gpm = 0.84 m^3/sec
C = 1.0 Btu/Ibmf
density of seawater ( d ) = 64 Ibm/ft3 = 1025.18 kg/m^3
rise in temp = 6 f
we have to make assumptions
- steady state
- fluid is in compressible and constant
first we calculate
mass flow rate of water ( Mw )
Mw = density of seawater * Q
= 64 * 13300 * 1/7.4804
= 113790 Ibm/min = 1896.51 Ibm/sec
therefore the rejection of the cooling water will be
= mass flow rate * C * rise in temperature
= 1896.51 * 1.0 * 6
= 11379.06 BTU/s (Qout)
Determine the amount of power generated using thermal efficiency formula
n =
W = power generated
n = thermal efficiency
Qout = rejection of cooling water
0.025 =
W = 0.025 W + 284.48
W ( 1 - 0.025 ) = 284.48
therefore W = 284.48 / 0.975
W = 291.77 BTU/s
note : 1 kw = 0.9478 BTU/s
x = 291.77 BTU/s
W in kw ( x ) = 291.77 / 0.9478 = 307.84 Kw
You might be interested in
Answer:
Tso = 28.15°C
Explanation:
given data
t2 = 21 mm
ki = 0.026 W/m K
t1 = 9 mm
kp = 180 W/m K
length of the roof is L = 13 m
net solar radiation into the roof = 107 W/m²
temperature of the inner surface Ts,i = -4°C
air temperature is T[infinity] = 29°C
convective heat transfer coefficient h = 47 W/m² K
solution
As when energy on the outer surface at roof of a refrigerated truck that is balance as
Q = .....................1
Q = .....................2
now we compare both equation 1 and 2 and put here value
solve it and we get
Tso = 28.153113
so Tso = 28.15°C
Answer:
The FSM uses the states along with the generation at the P output on each of the positive edges of the CLK. The memory stores the previous state in the machine and the decoder generates a P output based on the previous state.
Explanation:
The code is in the image.
Answer: C. There is no relationship
Explanation:
At the various temperatures, the flow rates do not seem to show any relation as similar temperatures can yield different flow rates.
The flow rates neither appear to generally increase nor decrease as a result of a decrease or an increase in temperature which means that there is a lack of a positive, negative and curvilinear relationship.
There is simply no relationship.
