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3 years ago

If engineering is easy then why don't most people join?

Engineering

2 answers:

Mazyrski [523]3 years ago

5 0

Engineering requires a lot of school

andreyandreev [35.5K]3 years ago

5 0

Answer: Engeenering needs to be perfect and got to go to school and you get all dirty.

Also please dome as brainlest

You might be interested in

Vending machine controller (adapted from Katz, "Contemporary Logic Design") Design and implement a finite state machine that con

babunello [35]

Answer:

Check the explanation

Explanation:

A vending machine controller is that type of machine that comes with a single serial port on the same chip as the programmable processor. The controller comprises of a port arbitrator that selectively attaches or links one of a number of serially communicating devices to this single serial port.

Kindly check the attached image to get the step by step explanation to the above question.

6 0

3 years ago

Un material determinado tiene un espesor de 30 cm y una conductividad térmica (K) de 0,04 w/m°C. En un instante dado la distribu

aksik [14]

Answer:

Para x=0:

$\phi=1.2 W/m^{2}$

Para x=30 cm:

$\phi=-2.4 W/m^{2}$

Explanation

Podemos utilizar la ley de Fourier par determinar el flujo de calor:

$\phi=-k\frac{dT}{dx}$ (1)

Por lo tanto debemos encontrar la derivada de T(x) con respecto a x primero.

Usando la ley de potencia para la derivda, tenemos:

$\frac{dT(x)}{dx}=300x-30$

Remplezando esta derivada en (1):

$\phi=-0.04(300x-30)$

Para x=0:

$\phi=0.04(30)$

$\phi=1.2 W/m^{2}$

Para x=30 cm:

$\phi=-0.04(300*0.3-30)$

$\phi=-2.4 W/m^{2}$

Espero que te haya ayudado!

4 0

3 years ago

In digital communication technologies, what is an internal network also known as?

garri49 [273]

Intranet is a network that is internal and use internet technologies. It makes information of any company accessible to its employees and hence facilitates collaboration. Same methods can be used to get information, use resources, and update the data as that of the internet.
Hopefully this helped.

4 0

3 years ago

What is the magnitude of the maximum stress that exists at the tip of an internal crack having a radius of curvature of 1.9 × 10

Fiesta28 [93]

Answer:

Recall the formula for the maximum stress, σₐ = 2σ₀ *√ (α/ρₓ)

where

σ₀ = tensile stress = 140 MPa = 1.40x 10⁸Pa

α = crack length = 3.8 × 10–2 mm = 3.8 x 10⁻⁵m

ρₓ = radius of curvature = 1.9 × 10⁻⁴mm = 1.9 × 10⁻⁷m

Substituting these values into the formula, we can calculate the max stress as

====== 2 x 1.40x 10⁸ x √(3.8 x 10⁻⁵/1.9 × 10⁻⁷)