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vekshin1
3 years ago
8

Learning Goal: To use fundamental geometric and statics methods to determine the state of plane stress at the point on an elemen

t of material that is rotated clockwise through an angle from the in-plane stress representation of the point on an element of material is shown. Let |σx| = 320 MPa , ∣∣σy∣∣ = 110 MPa , and ∣∣τxy∣∣ = 85.0 MPa . Use this information to represent the state of stress of the same point that is rotated through an angle of θ = 35.0 Part A - Normal and shear stress on element sectioned at plane a–a Using the element sectioned at plane a–a and the rotated coordinate system shown, determine the normal and shear stresses, σx′ and τx′y′, respectively, acting on plane a–a.Part B - Normal and shear stress on element sectioned at plane b–b Using the element sectioned at plane b–b and the rotated coordinate system shown, determine the normal and shear stresses acting on plane b–b.
Engineering
1 answer:
tiny-mole [99]3 years ago
5 0

Answer:

Please see the attached file for the Complete answer.

Explanation:

Download pdf
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a(n) ? is an intentionally constructed, low-impedance electrically conductive path designed and intended to carry current during
tester [92]

A effective ground-fault current path  is an intentionally constructed, low-impedance electrically conductive path designed and intended to carry current during ground-fault conditions from the point of grounding on a wiring system to the electrical supply source.

<h3>Is earth an effective ground fault current path?</h3>
  • Sticking the wire in the ground is not sufficient since the earth is not thought to be a reliable ground-fault current channel.
  • The electrical system of a building or other structure is based on grounding.
  • To give a fault current a secure path to travel, grounding is used.
  • When installing switches, light fixtures, appliances, and receptacles, a complete ground route must be kept.
  • The undesired current flow trips circuit breakers or blows fuses in a system that is correctly grounded.
  • Through the use of a grounding bank, effective grounding maintains voltages within predetermined limits during a line-to-ground fault (short-circuit condition).

To learn more about ground-fault current channel  refer,

brainly.com/question/28498355

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5 0
1 year ago
two pints of ethyl ether evaporate over a period of 1,5 hours. what is the air flow necessary to remain at 10% or less of ethyl
lesya692 [45]

The air flow necessary to remain at the lower explosive level is 4515. 04cfm

<h3>How to solve for the rate of air flow</h3>

First we have to find the rate of emission. This is solved as

2pints/1.5 x 1min

= 2/1.5x60

We have the following details

SG = 0.71

LEL = 1.9%

B = 10% = 0.1 a constant

The molecular weight is given as 74.12

Then we would have Q as

403*100*0.2222 / 74.12 * 0.71 * 0.1

= Q = 4515. 04

Hence we can conclude that the air flow necessary to remain at the lower explosive level is 4515. 04cfm

Read more on the rate of air flow on brainly.com/question/13289839

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7 0
2 years ago
Concerned with the number of maintenance visits the rocket can undergo before being out of service, you have been informed that
Ainat [17]

Answer:

(a) Mn = M₁ + (n-1) (M₂ -M₁) = 1 + (n- 1) 1 = n (b) n > 10 (exceed 10) or n =11 (c) n >50 or n= 51

After making a journey of 51 times, the rocket will be discarded

Explanation:

Solution

(a) Let Mn denotes the number of  maintenance visits after the nth journey

Then M₁ = 1 , M₂ = 1 +M₁ = 2, M₃ = 1 +M₂ = 3

We therefore, notice that M follows an arithmetic sequence

So,

Mn = M₁ + (n-1) (M₂ -M₁)

= 1 + (n- 1) 1 = n

or Mn =n

(b)  For what value of n we will get  fro Mn > 10

Thus,

n > 10 (exceed 10) or n =11

(c)Similarly of Mn is greater than 50 or Mn>50, the rocket will not be used or reused

So,

n >50 or n= 51

After making a journey of 51 times, the rocket will be discarded

7 0
4 years ago
Dos capacitores de placas paralelas, idénticos, pero con la excepción de que uno tiene el doble de separación entre sus placas q
Charra [1.4K]

Las características de la capacitancia permiten encontrar los resultados para las diferentes preguntas

1) El capacitor con menor distancia entre las placas tiene mayor campo eléctrico.

2) El capacitor con menor distancia tiene mayor carga

3) El capacitor con menor distancia tiene mayor densidad de carga

Los capacitores son sistema que sirve para acumular carga, esa formado por placas conductoras separadas una distancia pequeña, la capacitancia es  

             C = \frac{Q}{DV} = \frac{\epsilon_o A}{d}  

Donde Q es a carga, ΔV la diferencia de potencial, A el area y d la separación de las placas.

Busquemos las respuestas para las diferentes preguntas:

1) Cual tiene mayor campo eléctrico.

El potencial y el campo eléctrico están relacionados

            ΔV = - E d

            E = - \frac{\Delta V}{d}

Indican que un capacitor tiene el doble de separación de las placas que el otro

Capacitor 1

          E = - \frac{\Delta V}{d_1}  

Capacitor 2

         d₂ = 2 d₁  

         E₂ = - \frac{\Delta V}{2d_1}  

         E₂= ½ E₁

Por lo tanto el capacitor con menor distancia entre las placas tiene mayor campo eléctrico.

2) Cual tiene mas carga

Busquemos la carga para cada capacitor  

           Q = ε₀ \frac{A \Delta V}{d}  

Capacitor 1

           Q₁ = (ε₀ A ΔV) \frac{1}{d_1}

Capacitor 2

           Q₂ = (ε₀ A Δv) \frac{1}{2d_1}

           

            Q₂ = Q₁/2

       

El capacitor con menor distancia tiene mayor carga

3) Cual tiene mayor densidad de energía

La densidad de energía en un capacitor esta dada por

         u_E  = ½ ε₀ E²  

calculamos para cada capacitor

           

Capacitor 1

         u_{E\  1} = ½ ε₀ E₁²

Capacitor 2

         u_{E 2} = ½ ε₀ (E₁/2)²

por lo cual el capacitor con menor distancia tiene mas densidad de carga

En conclusión con lass característica de capacitancia podemos encontrar los resultados para las diferentes preguntas

     1) El capacitor con menor distancia entre las placas tiene mayor campo eléctrico.

    2) El capacitor con menor distancia tiene mayor carga

    3) El capacitor con menor distancia tiene mas densidad de carga  

Aprender mas aquí:  brainly.com/question/22813371

7 0
3 years ago
What is the volicity of a rocket?
Marysya12 [62]

Answer:

7.9 kilometers per second

Explanation:

8 0
3 years ago
Read 2 more answers
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