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Svetllana [295]
3 years ago
7

An academic or professional blog would be especially useful in which of the following fields?

Computers and Technology
2 answers:
Vesna [10]3 years ago
7 0
Blogs, even academic and professional, are not usually considered reliable sources. Most importantly, that's because they don't undergo the peer review process, which ensures the quality of the published papers (that they don't publish lies, in simple words).

So usually, you would prefer a published paper.

When then would you use a blog?
One such instance is when you want to find out about a quickly changing field , for example the newest standards in software development. So software engineering is one such field.

Another field is internet protection and security, as the viruses and the ways to defend against them also develop faster than can be published in a paper
Advocard [28]3 years ago
5 0

Answer:

The answer is Information Technology

Explanation:

Information Technology

Construction

Retail sales

Marketing

these were the 4 choices and the first one is correct

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In a non-price rationing system, consumers receive goods and services first-come, first served. Give me an example of a time whe
Anna35 [415]

When someone may be giving away something for free.

7 0
3 years ago
Write a program that declares and initializes a variable representing the weight in milligrams from the keyboard. The program di
Burka [1]

Answer:

weight = int(input("Enter weight in milligrams: "))

kilograms = int(weight / 1000000)

grams = int((weight - (kilograms * 1000000)) / 1000)

milligrams = weight - ((kilograms * 1000000) + (grams * 1000))

print("{} milligrams are equivalent to {} kilogram(s), {} gram(s), and {} milligram(s)".format(weight, kilograms, grams, milligrams))

Explanation:

*The code is in Python.

Ask the user to enter the weight and set it to the variable weight

Calculate the kilograms, divide the weight by 1000000 and cast the result to the int (If the weight is 1050042, kilograms would be 1050042/1000000 = 1)

Calculate the grams, subtract the kilograms from the weight, divide it by 1000 and cast the result to the int (If the weight is 1050042, grams would be int((1050042 - (1 * 1000000)) / 1000) = 50)

Calculate the milligrams, subtract the kilograms and grams from the weight (If the weight is 1050042, milligrams would be 1050042 - ((1 * 1000000) + (50 * 1000)) = 42)

Print the weight, kilograms, grams, and milligrams in the required format

3 0
3 years ago
Su now wants to highlight several inventors in her presentation, so she decides to use the underline color option.
Mars2501 [29]

Answer:

1. The home tab

2. Font group

3. The small arrow at the bottom right of the font command group.

4. On "Font" heading (then "All text" subheading)

Explanation:

The following explanation will help Su in accomplishing her task.

1. Go to the home tab;

2. From the home tab, Su will have access to various command groups but in her case, she needs the Font command group.

3. There's a small arrow located at the bottom left of the font command group section; clicking on this arrow will open the font dialogue.

4. On the font dialogue, there are two headings. The "font" heading and the "character spacing" heading.

In her case, she needs the "Font" heading. The font heading also has various subheadings. To access the underline colour option, she needs the "All text" subheading.

See attachment for picture guide.

7 0
4 years ago
For this exercise, we are going to take a look at an alternate Calculator class, but this one is broken. There are several scope
vekshin1

Answer:

public class Calculator {

   private int total;

   private int value;

   

   public Calculator(int startingValue){

       // no need to create a new total variable here, we need to set to the our instance total variable

       total = startingValue;

       value = 0;

   }

   public int add(int value){

       //same here, no need to create a new total variable. We need to add the value to the instance total variable

       total = total + value;

       return total;

   }

   /**

   * Adds the instance variable value to the total

   */

   public int add(){

       // no need to create a new total variable. We need to add the value to the instance total variable

       total += value;

       return total;

   }

   public int multiple(int value){

       // no need to create a new total variable. We need to multiply the instance total variable by value.

       total *= value;

       return total;

   }

   //We need to specify which value refers to which variable. Otherwise, there will be confusion. Since you declare the parameter as value, you need to put this keyword before the instance variable so that it will be distinguishable by the compiler.

   public void setValue(int value){

       this.value = value;

   }

   public int getValue(){

       return value;

   }

}

Explanation:

I fixed the errors. You may see them as comments in the code

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