Answer:
Step-by-step explanation:
Let E be the set of all even positive integers in the universe Z of integers,
i.e
E = {2,4,6,8,10 ....∞}
be the characteristic function of E.
∴
For XE(2)
since x is an element of E (i.e the set of all even numbers)
For XE(-2)
since - 2 is less than 0 , and -2 is not an element of E
For { x ∈ Z: XE(x) = 1}
This can be read as:
x which is and element of Z such that X is also an element of x which is equal to 1.
∴
E = {2,4,6,8,10 ....∞}
Answer:
A
Step-by-step explanation:
I think its awnser A 23.4
A. parallelogram
B. I believe it'd be around (11.2,7.5)
C. √(10-5)^2+(9-4)^2 = 21, so yes they bisect
<em>the</em><em> </em><em>pro</em><em>duct</em><em> </em><em>of</em><em> </em><em>2</em><em>6</em><em> </em><em>and</em><em> </em><em>x</em><em> </em><em>is</em><em> </em><em>wri</em><em>tten</em><em> </em><em>as</em>
<em>2</em><em>6</em><em> </em><em>times</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>2</em><em>6</em><em>x</em>
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Answer:
<h2>
v=(13,-3)</h2>
solution,
Therefore,
V=(13,-3)
Hope this helps...
Good luck on your assignment..