Answer:
d ≤ -0.5
Step-by-step explanation:
Multiply each term by -1
Answer:
C sorry if its wrong
Step-by-step explanation:
Answer:
The probability that the aircraft is overload = 0.9999
Yes , The pilot has to be take strict action .
Step-by-step explanation:
P.S - The exact question is -
Given - Before every flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the aircraft. The aircraft can carry 37 passengers, and a flight has fuel and baggage that allows for a total passenger load of 6,216 lb. The pilot sees that the plane is full and all passengers are men. The aircraft will be overloaded if the mean weight of the passengers is greater than 6216/37 = 168 lb. Assume that weight of men are normally distributed with a mean of 182.7 lb and a standard deviation of 39.6.
To find - What is the probability that the aircraft is overloaded ?
Should the pilot take any action to correct for an overloaded aircraft ?
Proof -
Given that,
Mean, μ = 182.7
Standard Deviation, σ = 39.6
Now,
Let X be the Weight of the men
Now,
Probability that the aircraft is loaded be
P(X > 168 ) = P(
)
= P( z >
)
= P( z > -0.371)
= 1 - P ( z ≤ -0.371 )
= 1 - P( z > 0.371)
= 1 - 0.00010363
= 0.9999
⇒P(X > 168) = 0.9999
As the probability of weight overload = 0.9999
So, The pilot has to be take strict action .
Answer:
(kgm^2) / (s^3)
Step-by-step explanation:
Comment if you want steps.
Answer:
Hay 3,875 litros de jugo multifrutal.
Step-by-step explanation:
<em>(Se asume que el problema fue propuesto en un país distinto a los Estados Unidos, razón por la cual se emplea las reglas del Sistema Internacional.)</em>
La capacidad de jugo multifrutal en el bidón se obtiene con la mezcla de cada jugo frutal y se logra mediante la suma de cada capacidad. A partir del enunciado, tenemos que la capacidad del jugo multifrutal es:



Hay 3,875 litros de jugo multifrutal.