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Vikki [24]
2 years ago
10

Find the missing length. Round to the nearest tenth, if necessary

Mathematics
2 answers:
mrs_skeptik [129]2 years ago
4 0
The answer to your question is B 17.7 when rounded to the nearest tenth
Dimas [21]2 years ago
3 0
19^2 = 361
7^2 = 49
361 - 49 = 312
Square root of 312 = 17.66
B) 17.7
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Answer: C Working out: (55,000 x 20) - (30,000 x 20) = $500,000 $1,100,000 - $600,000 =$500,000
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3 years ago
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How do I write 8.21 as a mixed number
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8 21/100
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5 0
3 years ago
PLEASE HELP THIS IS TIMED!!!! I WILL GIVE BRAINLIESTTTTTT
jekas [21]

Answer

Given: Sorry the images are at the bottom.

To find:

Part A: Write a sentence to compare the slope of the two functions and show the steps you used to determine the slope of f(x) and g(x).

Part B: Which function has a greater y-intercept? Justify your answer.

Solution:

On inspection of values of x and f(x) it is clear that f(x) is a linear function

i.e.

1)Slope of f(x) and y-intercept of f(x):

Convert the function in slope intercept form and calculate the slope.

Slope intercept form:

Here,

Slope of f(x)=1,

y-intercept of f(x)=(0,0)

2) Slope and y-intercept of g(x):

Slope of g(x)=7

Y-INTERCEPT of g(x) =(0,2)

Part A:

Slope of f(x) is 1 and slope of g(x) is 7.

Part B:

g(x) has a greater y-intercept.

Hope it helps you.

3 0
2 years ago
Show (2.3)(5.06) as a fraction multiplication problem
HACTEHA [7]
2.3 would be 2+(3/10), which we would then use a common denominator of 10 to get 20/10+3/10=23/10. 5.06 would be 5+(6/100). 6/100 can be reduced by a factor of 2 to 3/50, which we would then use a common denominator of 50 to get 250/50+3/50=253/50. As a fraction multiplication problem, this would look as (23/10)(253/50)
8 0
3 years ago
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​Cameron, Arthur, and Jamie are playing soccer. Their locations are recorded by a motion tracking system. The grid shows distanc
Luden [163]

Answer:

1. Arthur is about 54 meters away from Cameron.

2. Jamie is about 56 meters away from Cameron.

3. Arthur is closer to Cameron.

Step-by-step explanation:

We have been given the locations of Cameron (70,10), Arthur (20,30) and Jamie (45,60) on the the grid in meters.

1. To find the distances of Arthur and Jamie from Cameron we will use distance formula.

\text{Distance}=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

\text{Distance between Cameron and Arthur}=\sqrt{(70-20)^{2}+(10-30)^{2}}

\text{Distance between Cameron and Arthur}=\sqrt{(50)^{2}+(-20)^{2}}

\text{Distance between Cameron and Arthur}=\sqrt{2500+400}

\text{Distance between Cameron and Arthur}=\sqrt{2900}

\text{Distance between Cameron and Arthur}=53.8516480713450403\approx 54

Therefore, the distance Arthur is about 54 meters away from​ Cameron.

2. Let us find the distance between Cameron and Jamie.

\text{Distance between Cameron and Jamie}=\sqrt{(70-45)^{2}+(10-60)^{2}}

\text{Distance between Cameron and Jamie}=\sqrt{(25)^{2}+(-50)^{2}}

\text{Distance between Cameron and Jamie}=\sqrt{625+2500}

\text{Distance between Cameron and Jamie}=\sqrt{3125}

\text{Distance between Cameron and Jamie}=55.9016994374947424\approx 56

Therefore, Jamie is about 56 meters away from​ Cameron.

3. We can see that 56 is greater than 54, therefore, Arthur is closer to Cameron.


4 0
3 years ago
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