A local hamburger shop sold a total of 712 burgers on Tuesday
There are 62 more cheeseburgers than hamburgers
let cheeseburers = c
let hamburgers = h
h + 62 = c
c + h = 712
Plug in h + 62 for c
(h + 62) + h = 712
2h + 62 = 712
2h + 62 (-62) = 712 (-62)
2h = 650
2h/2 = 650/2
h = 325
There are 325 hamburgers sold on Tuesday
c = 325 + 62
c = 387
<em>There are 387 chesseburgers sold on tuesday </em>(in case you were wondering)
hope this helps
Answer:
x= -1/3 or -0.3
Step-by-step explanation:
Answer:
18
Step-by-step explanation:
For this problem, we will simply plug in the values of a and b into the respective variables in the expression 3ab to "evaluate" the expression.
a = 2; b = 3
3ab
Note, that when variables like a and b are smashed with a constant, the use of multiplication is in play.
3ab = 3 * a * b
With this in mind, let's plug in the values of a and b into the expression.
3ab
= 3 (2) (3)
= 3 (6)
= 18
Hence, 3ab evaluated when a=2 and b=3 is 18.
Cheers.
start with the ones and every time it goes over ten take the first number and add it to the tens for example 1+8+4+8=21 take the one and put it in the one spot below. Then take the 2 and add it to the six in the tens spot so it would be Instead of 6+8+3+2 it would be 8+8+3+2 which would equal 21 then put the 1 u=in the ten spot below add the 2 to the hundreds spot making is 5+5+7=4=14 put the 4 Below and add the 1 the the thousands making it 3+4+5+1=13 put the one on the ten thousands and put the three below the whole problem would be 13,411.
Answer:
d. not a real number
Step-by-step explanation:
it is not a real number because theres a negative under root
