Question

Please help, basic Algebra question

Answer 1

Answer:

The given expression  $(\frac{5}{6} a^{9}p^{5}) ^{3} = \frac{125}{216} \times a^{(27) } \times p^{(15)}$

Step-by-step explanation:

Here, the given expression is:  $(\frac{5}{6} a^{9}p^{5}) ^{3}$

Now, starting from the outer most bracket.

As we know :

$(abc)^{n} = (a)^{n} \times (b)^{n} \times (c)^{n}$

and $(a^m)^{n} = a^{(m \times n)}$

⇒ $(\frac{5}{6} a^{9}p^{5}) ^{3} = (\frac{5}{6})^{3} \times (a^{9})^{3} \times (p^{5}) ^{3}$

$=\frac{125}{216} \times (a)^{(9\times3) } \times (p)^{(5 \times 3)}\\= \frac{125}{216} \times a^{(27) } \times p^{(15)}$

Hence, the given expression  $(\frac{5}{6} a^{9}p^{5}) ^{3} = \frac{125}{216} \times a^{(27) } \times p^{(15)}$

Answer 2

Answer:

The algebraic expression result is $(\frac{125}{216})a^{27}p^{15}$

Step-by-step explanation:

The given algebraic expression is :

$(\frac{5}{6}a^{9}p^{5})^{3}$

Or, $(\frac{5}{6})^{3}(a^{9})^{3}(p^{5})^{3}$

Or, $(\frac{125}{216})a^{27}p^{15}$

Hence the algebraic expression result is $(\frac{125}{216})a^{27}p^{15}$ Answer