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jeka94
2 years ago
15

Please help, basic Algebra question

Mathematics
2 answers:
Tju [1.3M]2 years ago
7 0

Answer:

The given expression  (\frac{5}{6} a^{9}p^{5})  ^{3} = \frac{125}{216}  \times a^{(27) } \times p^{(15)}

Step-by-step explanation:

Here, the given expression is:  (\frac{5}{6} a^{9}p^{5})  ^{3}

Now, starting from the outer most bracket.

As we know :

(abc)^{n}   = (a)^{n} \times (b)^{n}  \times (c)^{n}

and (a^m)^{n} = a^{(m \times n)}

⇒ (\frac{5}{6} a^{9}p^{5})  ^{3} = (\frac{5}{6})^{3} \times (a^{9})^{3}   \times (p^{5}) ^{3}\\

=\frac{125}{216}  \times (a)^{(9\times3) } \times (p)^{(5 \times 3)}\\= \frac{125}{216}  \times a^{(27) } \times p^{(15)}

Hence, the given expression  (\frac{5}{6} a^{9}p^{5})  ^{3} = \frac{125}{216}  \times a^{(27) } \times p^{(15)}

myrzilka [38]2 years ago
6 0

Answer:

The algebraic expression result is (\frac{125}{216})a^{27}p^{15}

Step-by-step explanation:

The given algebraic expression is :

(\frac{5}{6}a^{9}p^{5})^{3}

Or, (\frac{5}{6})^{3}(a^{9})^{3}(p^{5})^{3}

Or, (\frac{125}{216})a^{27}p^{15}

Hence the algebraic expression result is (\frac{125}{216})a^{27}p^{15} Answer

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