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nika2105 [10]
3 years ago
8

Please help me!!!!! I'll give brainlest if correct!

Mathematics
1 answer:
inn [45]3 years ago
3 0

Answer:                                  

Step-by-step explanation:

You might be interested in
The number of people arriving at a ballpark is random, with a Poisson distributed arrival. If the mean number of arrivals is 10,
Stella [2.4K]

Answer:

a) 3.47% probability that there will be exactly 15 arrivals.

b) 58.31% probability that there are no more than 10 arrivals.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

If the mean number of arrivals is 10

This means that \mu = 10

(a) that there will be exactly 15 arrivals?

This is P(X = 15). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 15) = \frac{e^{-10}*(10)^{15}}{(15)!} = 0.0347

3.47% probability that there will be exactly 15 arrivals.

(b) no more than 10 arrivals?

This is P(X \leq 10)

P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-10}*(10)^{0}}{(0)!} = 0.000045

P(X = 1) = \frac{e^{-10}*(10)^{1}}{(1)!} = 0.00045

P(X = 2) = \frac{e^{-10}*(10)^{2}}{(2)!} = 0.0023

P(X = 3) = \frac{e^{-10}*(10)^{3}}{(3)!} = 0.0076

P(X = 4) = \frac{e^{-10}*(10)^{4}}{(4)!} = 0.0189

P(X = 5) = \frac{e^{-10}*(10)^{5}}{(5)!} = 0.0378

P(X = 6) = \frac{e^{-10}*(10)^{6}}{(6)!} = 0.0631

P(X = 7) = \frac{e^{-10}*(10)^{7}}{(7)!} = 0.0901

P(X = 8) = \frac{e^{-10}*(10)^{8}}{(8)!} = 0.1126

P(X = 9) = \frac{e^{-10}*(10)^{9}}{(9)!} = 0.1251

P(X = 10) = \frac{e^{-10}*(10)^{10}}{(10)!} = 0.1251

P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.000045 + 0.00045 + 0.0023 + 0.0076 + 0.0189 + 0.0378 + 0.0631 + 0.0901 + 0.1126 + 0.1251 + 0.1251 = 0.5831

58.31% probability that there are no more than 10 arrivals.

8 0
3 years ago
6cos(20πt-π)+6√3cos(20πt-π\2)
juin [17]

Answer:

<u>Answer</u><u> </u><u>is</u><u> </u><u>-</u><u>6</u><u>t</u>

Step-by-step explanation:

{ \tt{ = (6 \cos(20\pi t)  \cos(\pi)  +  6\sin(20\pi t) \sin(\pi) ) + 6 \sqrt{3} ( \cos(20\pi t)  \cos( \frac{\pi}{2} )  +  \sin(20\pi t)   \sin( \frac{\pi}{2} )) }} \\  = { \tt{ (- 6t + 0) + (0 + 0)}} \\  = { \tt{ - 6t}}

Note that π is 180°

5 0
3 years ago
Need help on this please
Akimi4 [234]
Question 10
30-2=28

28*2= 56
56*2= 112
120*2= 240

240+112=352.

Area = 352 square feet
Question 11
Volume = pi*r*r*h
=3.142*2.5*2.5*0.5
= 9.817
From the choices the answer is
D. 9.8 cubic ft
7 0
3 years ago
A computer company has a special going in which all customers receive a free monitor and scanner with the purchase of a new comp
kipiarov [429]

Answer:

2160

Step-by-step explanation:

Given : At a computer​ store, a customer is considering 10 different​ computers, 6 different​ monitors, 9 different printers and 4 different scanners. We assume that each of the components is compatible with one another and that one of each is to be​ selected. then by Fundamental counting principle , the number of different computer systems possible is given by :-

10x6x9x4= 2160

Hence, the number of different computer systems possible= 2160The Fundamental Counting Principle is a technique in Mathematics to calculate the number of possible outcomes by multiplying the events together .

HOPE THIS HELPED ;3

7 0
3 years ago
What is 6 to the 4 power times 6 to the 4th power?
alexdok [17]

Answer:

Your answer is 1679616

Step-by-step explanation:

6 x 6 x 6 x 6=1296

6 x 6 x 6 x 6=1296

1296 x 1296=

1679616

6 0
3 years ago
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