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liraira [26]
3 years ago
9

In an ordered pair,the x-coordinate represents the number of hexagons and the y-coordinate represents the total number of sides.

If the x-coordinate is 7, what is the y coordinate
Mathematics
1 answer:
Novosadov [1.4K]3 years ago
6 0
The y-coordinate would be 42.

Hexagons have 6 sides.  The x-coordinate is the number of hexagons; since our x-coordinate is 7, that means 7 hexagons.  

The y-coordinate is the total number of sides.  7 hexagons * 6 sides per hexagon = 42 sides.
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sleet_krkn [62]

Answer:

60% OF 6 = 3.6

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Step-by-step explanation:

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The correct answer is B.

+ 15 represents the 15 miles she already ran.

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How many solution does -3 (4 - 3x) = 9x - 12
daser333 [38]

Answer: infinite solutions

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(−3) (4) + (−3) (−3x) = 9x + −12

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3 years ago
Describe the steps required to determine the equation of a quadratic function given its zeros and a point.
faltersainse [42]

Answer:

Procedure:

1) Form a system of 3 linear equations based on the two zeroes and a point.

2) Solve the resulting system by analytical methods.

3) Substitute all coefficients.

Step-by-step explanation:

A quadratic function is a polynomial of the form:

y = a\cdot x^{2}+b\cdot x + c (1)

Where:

x - Independent variable.

y - Dependent variable.

a, b, c - Coefficients.

A value of x is a zero of the quadratic function if and only if y = 0. By Fundamental Theorem of Algebra, quadratic functions with real coefficients may have two real solutions. We know the following three points: A(x,y) = (r_{1}, 0), B(x,y) = (r_{2},0) and C(x,y) = (x,y)

Based on such information, we form the following system of linear equations:

a\cdot r_{1}^{2}+b\cdot r_{1} + c = 0 (2)

a\cdot r_{2}^{2}+b\cdot r_{2} + c = 0 (3)

a\cdot x^{2} + b\cdot x + c = y (4)

There are several forms of solving the system of equations. We decide to solve for all coefficients by determinants:

a = \frac{\left|\begin{array}{ccc}0&r_{1}&1\\0&r_{2}&1\\y&x&1\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }

a = \frac{y\cdot r_{1}-y\cdot r_{2}}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x+x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}

a = \frac{y\cdot (r_{1}-r_{2})}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x +x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}

b = \frac{\left|\begin{array}{ccc}r_{1}^{2}&0&1\\r_{2}^{2}&0&1\\x^{2}&y&1\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }

b = \frac{(r_{2}^{2}-r_{1}^{2})\cdot y}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x +x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}

c = \frac{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&0\\r_{2}^{2}&r_{2}&0\\x^{2}&x&y\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }

c = \frac{(r_{1}^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1})\cdot y}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x + x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}

And finally we obtain the equation of the quadratic function given two zeroes and a point.

6 0
3 years ago
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