Ask question

Ask question

All categories

3 years ago

15

A group of 55 students and five chaperones is going on a field trip. The buses can hold 25 people. How many buses will this grou

p need?

1 answer:

stepan [7]3 years ago

5 0

Answer:

3 Buses

Step-by-step explanation:

55 students and 5 chaperones

one bus holds 25

2 buses would hold 50

need one more bus for remaining 5 students and 5 chaperones

therefore the group will need 3 Buses

You might be interested in

Find all factors of 2x^3-3x^2-2x

Nesterboy [21]

ANSWER:

x, 2x + 1, x -2

STEP-BY-STEP EXPLANATION:

We have the following expression:

$2x^3-3x^2-2x$

We simplify as follows to determine the factors:

$\begin{gathered} \text{ We factor the common term:} \\ \\ x\left(2x^2-3x-2\right) \\ \\ \text{ Now we factor the following term} \\ \\ 2x^2-3x-2 \\ \\ -3x=x-4x \\ \\ 2x^2+x-4x-2 \\ \\ \left(2x^2+x\right)+\left(-4x-2\right) \\ \\ x\left(2x+1\right)-2\left(2x+1\right) \\ \\ \left(2x+1\right)\left(x-2\right) \\ \\ \text{ Therefore:} \\ \\ 2x^3-3x^2-2x=x\left(2x+1\right)\left(x-2\right) \end{gathered}$

The factors would be x, 2x + 1, x -2

7 0

1 year ago

In the figure below, secant PQ intersects the circle at R and secant SQ intersects the circle at point T. What is the value of z

BabaBlast [244]

Answer:

19

Step-by-step explanation:

6×(6+14) = 5×(5+z)

120 = 25 + 5z

95 = 5z

z = 19

6 0

2 years ago

Please help! Will give Brainliest!

Serhud [2]

Answer:

A

Step-by-step explanation:

8 0

3 years ago

dentify the vertical asymptotes of f(x) = quantity x plus 6 over quantity x squared minus 9x plus 18.

ser-zykov [4K]

So the function we're dealing with is

f(x) = $\frac{x+6}{x^{2}-9x+18 }$

Factorising we get, $x^{2} -9x+18=0$
$(x-3)(x-6)=0$

Therefore, the vertical asymptotes are at x = 3 and x = 6

8 0

3 years ago

Please help me !!!

kati45 [8]

$23)~75r^2-48=3(25r^2-16)=3(5r-4)(5r+4)\\\\
24)~45x^2-5=5(9x^2-1)=5(3x-1)(3x+1)\\\\
25)~m^3n-mn^3=mn(m^2-n^2)=mn(m-n)(m+n)\\\\
26)~6a^3-24ab^2=6a(a^2-4b^2)=6a(a-2b)(a+2b)\\\\
27)~3x^2+15x-72=3(x^2+5x-24)=3(x-3)(x+8)\\\\
28)~2m^2-4m+2=2(m^2-2m+1)=2(m-1)^2\\\\
29)~x^3+9x^2-52x=x(x^2+9x-52)=x(x-4)(x+13)\\\\
30)~4y^3+4y^2-120y=4y(y^2+y-30)=4y(y-5)(y+6)$

5 0

3 years ago

Read 2 more answers