The height of the object after 1 sec is 284 feet
<h3>Equation of height of an object</h3>
Given the equation of height of an object expressed as:
h(t) = -16t^2 + 300t
We are to find the height of the object after 1 sec. To do that, we will substitute t = 1 into the following expression
h(t) = -16t^2 + 300t
h(1) = -16(1)^2 + 300(1)
h(1) = -16 + 300
h(1) = 284ft
Hence the height of the object after 1 sec is 284 feet
Learn more on maximum height here: brainly.com/question/12446886
7/8
3/10 of 7/8 means 3/10 times 7/8=21/80
1hour=60mins
60 times 21/80=1260/80=15.75
answer is 15.75 mins
<span>3y = x + 6
y – x = 3 -----------> x=y - 3 (substitute in 1st equation)
3y = y - 3 +6
3y - y = 3
2y = 3
y = 2/3
x= y - 3 = 2/3 -3 = 2/3 - 9/3 = - 7/3
</span>x= - 7/3, y = 2/3<span>
</span>
Answer:
The Answer is C.
Step-by-step explanation:
