All categories

3 years ago

Simplify (15+6)^2-(8-5)^2

1 answer:

3 0

Use "PEMDAS" (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction) to know what to do first.

(15 + 6)^{2} - (8 - 5)^{2} Solve the insides of the parentheses
21^{2} - 3^{2} Solve the exponents (21 x 21) and (3 x 3)
441 - 9 Subtract
432

You might be interested in

A worker at a factory earns $12 per hour plus 2.50 for each unit produced that hour. The worker earns a total of $27 in one hour

nevsk [136]

Answer:

The total number of units produced is 6 .

Step-by-step explanation:

Given as :

The earning of worker at the factory = $ 12 per hour + $ 2.50 each unit per hour

The total earning of worker per hour = $ 27

Let The total number of unit produced = x

According to question

The wage worker earn per hour + earning × per unit produced that hour = Total earning of worker per hour

Or, $ 12 per hour + $ 2.50 each unit per hour × x = $ 27

Or, $ 2.50 each unit per hour × x = $ 27 - $ 12

Or, $ 2.50 each unit per hour × x = $ 15

∴ x = $\frac{15}{2.50}$

Or, x = 6

Hence The total number of units produced is 6 . Answer

4 0

2 years ago

A sphere has a diameter of 15 inches.

s344n2d4d5 [400]

Your answer is d.14,230.0in^3

8 0

3 years ago

Read 2 more answers

May someone help me out with this question please

mario62 [17]

You would have 60 different types of pens with this brand. You need to multiply 12 and 5 (because you have 12 different colors for every type of tip, so you have 5 groups of 12).

8 0

2 years ago

a fruit delivers its fruit in two types of boxes: large and small. a delivery of 3 large boxes and 5 small boxes has a total wei

Masteriza [31]

Answer:

The weight of a small box = 13.5 kg

The weight of 1 large box = 18.5 kg

Step-by-step explanation:

Let us assume the weight of a small box = m kg

And the weight of 1 large box = n kg

Now, the weight of 5 small box = 5 x (weight of 1 small box) = 5 m

Also, the weight of 3 large box = 3 x (weight of 1 large box) = 3 n

Here, 3 large boxes + 5 small boxes = of 123 kilograms

⇒ 5 m + 3 n = 123 .... (1)

Again, the weight of 2 small box = 2 x (weight of 1 small box) = 2 m

Also, the weight of 12 large box = 12 x (weight of 1 large box) = 12 n

Here, 12 large boxes + 2 small boxes = 249 kilograms

⇒ 2 m+ 12 n = 249 .... (2)

Now, solving both the given equations by ELIMINATION, we get:

5 m + 3 n = 123 x (2)

2 m+ 12 n = 249 x (-5)

we get the new set of equitation as:

10 m + 6 n = 246

- 10 m - 60 n = -1245

Adding both equation, we get

-54 n = 999

or, n = 18.5

Now, 5 m + 3 n = 123

So, 5 m = 123 -3 (18.5) = 123 - 55.5 = 67.5

⇒ m = 13.5

Hence, the weight of a small box = m kg = 13.5 kg

And the weight of 1 large box = n kg = 18.5 kg

8 0

2 years ago

I need help explain “how to find” these probabilities, thanks a lot

USPshnik [31]

answer is attached below with full explanation

3 0

2 years ago