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Vesnalui [34]
3 years ago
13

A picture measuring 2.5" high by 6" wide is to be enlarged so that the widths now 18 inches. How tall will the picture be?

Mathematics
1 answer:
Alecsey [184]3 years ago
6 0
The picture is 7.5” tall because you multiply 6 by 3 to get 18 so you do the same to 2.5 and you get 7.5”
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Hep meh plz again 20 points
Alchen [17]
The answer is the last one. After you multiply the following 2 number sets you get 414. so multiply 9 by the given answers and whichever equals 414 that is you answer. (its d btw)
8 0
3 years ago
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It’s a 4 digit number. The tens are double the ones. The thousands are double the tens. The sum of the digit is 19
Zielflug [23.3K]
The tens are double the ones: c= 2d
the thousands are double the tens:
a = 2c = 4d
the sum of the digits is 19:: a+b+c+ d = 19

Substitute for a and c to get:
4d + b + 2d + d = 19
b + 7d = 19
d=2;b=5;0=4;a=8
Ans:8542
7 0
2 years ago
Which is closest to the volume of a cylinder with a height of 11 inches and
Veseljchak [2.6K]

Answer:

The closest to the volume of cylinder is <u>63 in.³</u>.

Step-by-step explanation:

Given:

Cylinder with a height of 11 inches and  a circumference of 8 1/2 inches.

Now, to find the volume.

As circumference is given we get the radius by putting formula:

Circumference = 8 1/2 inches = 17/2 inches.

Let the radius be r.

Circumference=2\pi r

<em>Taking the value of π = 3.14.</em>

\frac{17}{2}=2\times 3.14\times r

8.5=6.28\times r

<em>Dividing both sides by 6.28 we get:</em>

1.35=r

So, radius = 1.35 inches.

Height = 11 inches.

Now, putting the formula to get the volume:

Volume=\pi r^2h

Volume=3.14\times 1.35^2\times 11

Volume=3.14\times 1.8225\times 11

Volume=3.14\times 20.0475

Volume=62.949\ inches^3

<u><em>Hence, the volume of cylinder = 63 inches³ (approximately).</em></u>

Therefore, the closest to the volume of cylinder is 63 in.³.

4 0
3 years ago
Part A: Solve –mk – 90 &gt; 85 for m. Show your work. (4 points)
olganol [36]
A:MK <-175 if k >0, then m <-175/m, if k=0, no answers, if k <0,  then m >-175/m 


B: 5f=3c-55, then f = 3c-55/5
4 0
4 years ago
Read 2 more answers
A ​17-foot ladder is placed against a vertical wall of a​ building, with the bottom of the ladder standing on level ground feet
artcher [175]

Answer:

15 feet..

taking base as 8m

Given: ladder = 17 m and base = 8 m

The ladder forms a right triangle with the base of 8 m, the wall will be 15 m and the ladder (hypotenuse) is 17 m.

Let’s say you did not know that this was a standard 8–15–17 right triangle.

This is how you can figure it out:

hypotenuse(h)22 = side2112 + side2222

Let side11 = base and side22 = wall

1722 = 822 + wall22

wall = 172−82−−−−−−−√172−82

wall = 289−64−−−−−−−√289−64

wall = 225−−−√225

wall = 15 feet

5 0
3 years ago
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