Answer:
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The sweatshirt size which the vendor should bring more of by virtue of that which is most likely to be sold is; Choice A; Extra-large.
<h3>Which sweatshirt size should the vendor bring more of?</h3>
If follows from the task content that the
ratio of extralarge shirts sold relative to the quantity he had to sell is
= 99/108
= 11/12,
This is a ratio which is larger than any other shirt.
Consequently, the vendor must bring more of the X-large shirts to avoid running out of them.
Read more on ratios;
brainly.com/question/13513438
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<h2>
Answer:</h2>
The marginal cost when x=8 is:
375
<h2>
Step-by-step explanation:</h2>
We know that the marginal function for a cost function C(x) at x=a
is given by:
C'(x) at x=a
Here we have the cost function C(x) as:
Now we find the derivative of C(x) with respect to x.
i.e.
( Since,
)
Hence, we get:
A)We have been given →
Hieght of trough = 5m
length of trough = 6m
Breadth of trough = 4m
so , As the top is opened for feeding animals.
Area of base = length× Breadth
= (6×4) m²
= 24 m²
Area of Front and back face = Hieght × length
= (5×6) m²
= 30m²
Area of side faces = hieght × Breadth
= (5×4) m²
= 20 m²
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B)Total Surface area of trough will be given by formula - 2(lb+bh+hl)
= 2{(6×4)+(4×5)+(5×6)}
= 2{24+20+30}
= 2×74
= 148 m²
As we have been told top is open , so we will deduct top from Total surface Area to obtain Surface area →
(148-24) m²
(Area of top will be same as base area , that is 24m² as we have solved in A)
= 124m²
Answer→ Surface area of trough is 124m²
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