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Oxana [17]
3 years ago
10

5. While bird watching, Gabrielle saw 6 robins and 3 blue jays.

Mathematics
1 answer:
Semenov [28]3 years ago
4 0

Answer:

Neither. They both saw the same amount of birds.

Step-by-step explanation:

Gabrielle saw 9 birds, but so did Chase. 6+3 is 9. 3+6 is also 9. The commutative property of addition states that a+b=b+a.

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How many terms are in the binomial expansion of (3x + 5)9? 8 9 10 11
Stells [14]
The number of terms in the binomial expansion of (3x-5)^9 is 10
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3 years ago
Read 2 more answers
Please answer and no explanation needed
rewona [7]
Wait isn’t it 30 or am I reading it wrong?
3 0
3 years ago
Hi does anyone know how to solve this question if so please show the working out.
tester [92]

Explanation:

The Law of Sines is your friend, as is the Pythagorean theorem.

Label the unmarked slanted segments "a" and "b" with "b" being the hypotenuse of the right triangle, and "a" being the common segment between the 45° and 60° angles.

Then we have from the Pythagorean theorem ...

  b² = 4² +(2√2)² = 24

  b = √24

From the Law of Sines, we know that ...

  b/sin(60°) = a/sin(θ)

  y/sin(45°) = a/sin(φ)

Solving the first of these equations for "a" and the second for "y", we get ...

  a = b·sin(θ)/sin(60°)

and ...

  y = a·sin(45°)/sin(φ)

Substituting for "a" into the second equation, we get ...

  y = b·sin(θ)/sin(60°)·sin(45°)/sin(φ) = (b·sin(45°)/sin(60°))·sin(θ)/sin(φ)

So, we need to find the value of the coefficient ...

  b·sin(45°)/sin(60°) = (√24·(√2)/2)/((√3)/2)

  = √(24·2/3) = √16 = 4

and that completes the development:

  y = 4·sin(θ)/sin(φ)

6 0
3 years ago
Help plzzz idc which one you choose. And Thank you!!!!!! :/
KonstantinChe [14]

Answer:

rip 0 answers on this

Step-by-step explanation:

7 0
3 years ago
Solve for x. Leave your answer in simplest radical form.
strojnjashka [21]

There are two Right angled triangles in the given figure, with two missing sides, let's name the other missing side be " y "

According to Pythagoras theorem,

\boxed{ \large \boxed{h {}^{2}  =  {b}^{2} + p{}^{2}  }}

note :

  • p = perpendicular / opposite side
  • b = base / adjacent side
  • h = hypotenuse

let's solve for " y² " first ( square of other missing side )

➢ \:  \:  {y}^{2}  =  {8}^{2}  + 3 {}^{2}

➢ \:  \:  {y}^{2}  = 64 + 9

➢ \:  \:  {y}^{2}  = 73

now let's solve for " x " , by using pythagorous theorem

➢ \:  \:  {x}^{2}  =  {y}^{2}  +  {6}^{2}

➢ \:  \:  {x}^{2}  = 73 + 36

➢ \:  \:x {}^{2}  =  109

➢ \:  \: x =  \sqrt{109}

Approximate :

➢ \:  \: 10.44 \:  \: units

\mathrm{✌TeeNForeveR✌}

5 0
3 years ago
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