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3 years ago

Sandy is working with a carpenter to frame a house

Mathematics

1 answer:

mafiozo [28]3 years ago

3 0

Answer:

umm gotta be specific how long is the frame?

Step-by-step explanation:

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The number of boys to the number of girls in the seventh grade is 5/7 . There are 125 boys in the seventh grade. What is the tot

VARVARA [1.3K]

5 boys because if you add 5x5x5

If 1 = 5, 2 = 25, 3 = 125, like dat

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3 years ago

A salesperson at a jewelry store earns 5% commission each week. Last week, Jarrod sold $640 worth of jewelry. How much did he

Aleksandr-060686 [28]

Answer:

$32

Step-by-step explanation:

To find the commission, multiply the rate by the sales:

commission = 5% × $640 = $32

He made $32 in commission.

<em>Additional comment</em>

Many calculators and all spreadsheets can work with percentages directly. If yours can't, or if you can't do this arithmetic mentally, you can use the equivalent decimal or fraction for 5%.

5% = 5/100 = 0.05 = 1/20

Then 5% × $640 = $640/20 = $64/2 = $32.

3 0

3 years ago

Read 2 more answers

Can anyone help me with this problem

Anit [1.1K]

I hope this helps you

8 0

4 years ago

A driver is 19 meters below the surface of the water. Use an integer to represent how far the driver will need to travel to reac

Tresset [83]

Answer:

19 metres

Step-by-step explanation:

3 0

3 years ago

The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.

Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m + 40 m + c = 120 m

61 m + c = 120 m

c = 120 m - 61 m

c = 59 m

↓ ↓

A → → → → → → → → → → → C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

$a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0$

Angle B is calculated as follows;

$Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0$

Angle C is calculated as follows;

$Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0$

Therefore, the largest angle of the field is 149⁰.

8 0

3 years ago