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AveGali [126]
3 years ago
12

How did you actually solve for y and x

Mathematics
2 answers:
Softa [21]3 years ago
8 0
Is this for someone in particular?? But it depends on the equation you are doing
PSYCHO15rus [73]3 years ago
3 0
Do you mean the y access and the x access
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Which graph represents the function below?
KATRIN_1 [288]
The answer to this problem is A
3 0
3 years ago
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Find the circumference of a circle with a diameter of 15 inches... Round to the nearest tenth and include units in your answer..
rosijanka [135]

Answer:

<em>47. 1 inches ; where inches ⇒ units</em>

Step-by-step explanation:

Consider the Circumference as such;

Diameter - 15 inches,\\Circumference - 2\pi r, r - radius,\\\\2\pi r = \pi d, d - diameter ( considering, 2 * r = diameter )\\\\Circumference = \pi * d = \pi * diameter = \pi * 15 = ( About ) 47.1 inches\\Solution; Circumference = ( About ) 47.1 inches

<em>From this we can tell that ⇒ Answer; 47. 1 inches, where inches - units</em>

6 0
3 years ago
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At the Roberts family reunion, there are 48 men. The ratio of men to women is 6.5. How many women are at the reunion
ruslelena [56]
Your answer would be approximately 30 women because:
40/6=6.6 (repeating)
since there cant be .6 of a woman, we will get rid of .6
now we have 40/6=6
finally:
6*5= 30

i hope this helps you! :)
7 0
3 years ago
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In the xy-plane, the graph of x2 − 4x + y2 − 6y = −8 is a circle. What is the radius of the circle?
Blizzard [7]

The center-radius form of the circle equation

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have:

x^2-4x+y^2-6y=-8

Use

(a-b)^2=a^2-2ab+b^2\qquad(*)

x^2-2(x)(2)+y^2-2(y)(3)=-8\qquad\text{add}\ 2^2\ \text{and}\ 3^2\ \text{to both sides}\\\\\underbrace{x^2-2(x)(2)+2^2}_{(*)}+\underbrace{y^2-2(y)(3)+3^2}_{(*)}=2^2+3^2-8\\\\(x-2)^2+(y-3)^2=4+9-8\\\\(x-2)^2+(y-3)^2=5\\\\(x-2)^2+(y-3)^2=(\sqrt5)^2\\\\Answer:\\\\\boxed{center:(2,\ 3)}\\\\\boxed{radius:r=\sqrt5}

4 0
3 years ago
What is 4 over 9 1 over 9
kirill [66]
<span>So the solution is 4/3</span>
5 0
3 years ago
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