Answer:
The probability that the last card dealt is an ace is
.
Step-by-step explanation:
Given : A deck of ordinary cards is shuffled and 13 cards are dealt.
To find : What is the probability that the last card dealt is an ace?
Solution :
There are total 52 cards.
The total arrangement of cards is 52!.
There is 4 ace cards in total.
Arrangement for containing ace as the 13th card is
.
The probability that the last card dealt is an ace is




Therefore, the probability that the last card dealt is an ace is
.
1.) The sum(addition) of 21 and 5 times(multiplication) a number f is(=) 61.
f = unknown number/variable [So 21 plus 5f(5 times f) equals 61]
21 + 5f = 61 [21(one-time) + 5f(number x variable) = 61(total)]
2.) Seventeen more(addition) than seven times(multiplication) a number j is(=) 87.
j = unknown number/variable [So 17 plus 7j(7 times j) equals 87]
17 + 7j = 87
3.) n = number of calls
18 + 0.05n = 50.50
[Company charges $18 plus five cents per call(n), and the total charge was $50.50]
4.) s = the number of students
40 + 30s = 220
[Tutor charges $40 plus $30 per student(s), and the total charge was $220]
height:length
1:2
x feet: 5 feet
You know the length and the ratio of the dimensions. From the ratio you know that the length is twice the height. So height = 5/2 = 2.5 ft.
Answer:
9/16
Step-by-step explanation:
3/2 / 8/3 =
3/2 x 3/8 = 9/16
Hope that helps!
Answer:
2 67/100
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